使用Spring实现Oauth2。我想实现隐式工作流程:
我的配置文件:
@Configuration
@EnableAutoConfiguration
@RestController
public class App {
@Autowired
private DataSource dataSource;
public static void main(String[] args) {
SpringApplication.run(App.class, args);
}
@RequestMapping("/")
public String home() {
return "Hello World";
}
@Configuration
@EnableResourceServer
protected static class ResourceServer extends ResourceServerConfigurerAdapter {
@Autowired
private TokenStore tokenStore;
@Override
public void configure(ResourceServerSecurityConfigurer resources)
throws Exception {
resources.tokenStore(tokenStore);
}
@Override
public void configure(HttpSecurity http) throws Exception {
// @formatter:off
http.authorizeRequests().antMatchers("/oauth/token").authenticated()
.and()
.authorizeRequests().anyRequest().permitAll()
.and()
.formLogin().loginPage("/login").permitAll()
.and()
.csrf().disable();
}
}
@Configuration
@EnableAuthorizationServer
protected static class OAuth2Config extends AuthorizationServerConfigurerAdapter {
@Autowired
private AuthenticationManager auth;
private BCryptPasswordEncoder passwordEncoder = new BCryptPasswordEncoder();
@Bean
public JdbcTokenStore tokenStore() {
return new JdbcTokenStore(DBConnector.dataSource);
}
@Bean
protected AuthorizationCodeServices authorizationCodeServices() {
return new JdbcAuthorizationCodeServices(DBConnector.dataSource);
}
@Override
public void configure(AuthorizationServerSecurityConfigurer security)
throws Exception {
security.passwordEncoder(passwordEncoder);
}
@Override
public void configure(AuthorizationServerEndpointsConfigurer endpoints)
throws Exception {
endpoints.authorizationCodeServices(authorizationCodeServices())
.authenticationManager(auth).tokenStore(tokenStore())
.approvalStoreDisabled();
}
@Override
public void configure(ClientDetailsServiceConfigurer clients) throws Exception {
// @formatter:off
clients.jdbc(DBConnector.dataSource)
.passwordEncoder(passwordEncoder)
.withClient("my-trusted-client")
.secret("test")
.authorizedGrantTypes("password", "authorization_code",
"refresh_token", "implicit")
.authorities("ROLE_CLIENT", "ROLE_TRUSTED_CLIENT")
.scopes("read", "write", "trust")
.resourceIds("oauth2-resource")
.accessTokenValiditySeconds(0);
// @formatter:on
}
}
@Autowired
public void init(AuthenticationManagerBuilder auth) throws Exception {
// @formatter:off
auth.jdbcAuthentication().dataSource(DBConnector.dataSource).withUser("dave")
.password("secret").roles("USER");
// @formatter:on
}
}
到目前为止这是有效的。用户也在数据库中生成。
问题如下。当我尝试执行以下请求时:
我总是得到一个弹出窗口(身份验证),要求我输入用户名和密码。但是我从那里进入的东西并不重要。那有什么不对?
我想拥有它,当我打电话给这个网址时,我会收回我的access_token。
答案 0 :(得分:4)
在隐式流的情况下,所有令牌都将通过授权URL而不是令牌url生成。所以你应该用隐式响应类型命中../oauth/authorize端点。即
../oauth/authorize?response_type=implicit&client_id=trusted_client&redirect_uri=<redirect-uri-of-client-application>.
您正在获取用户名密码popup,因为令牌端点已经通过spring的BasicAuthenticationFilter受到保护,并且它希望您将client_id作为用户名传递并将client_secret作为密码传递。您需要保护授权端点,而不是令牌端点,以便按照给定的端点安全配置进行...
@Override
public void configure(HttpSecurity http) throws Exception {
// @formatter:off
http.authorizeRequests().antMatchers("/oauth/authorize").authenticated()
.and()
.authorizeRequests().anyRequest().permitAll()
.and()
.formLogin().loginPage("/login").permitAll()
.and()
.csrf().disable();
}