Question

当我点击tableview单元格时，它将转到下一个视图，它将显示电话和名称

switch (rowtype) {
    case PhoneRow:
    {
        cell = [self.tableView dequeueReusableCellWithIdentifier:reusableIdentifierNormalCell];
        cell.titleLabel.text = [NSString stringWithFormat:NSLocalizedString(@"Call %@", nil), self.ecpInfo[@"Name"]];
        cell.subtitleLabel.text = phoneNumber;
        cell.iconImageView.image = [UIImage imageNamed:@"TelephoneIcon"];
        cell.tag = ECPDetails_RowTagsStart + rowtype;
    }

当我执行此行时，它显示输出就像致电

Answer 1

试试这个，

添加此宏：

#define IS_EMPTY(value) (value == (id)[NSNull null] || value == nil || ([value isKindOfClass:[NSString class]] && ([value isEqualToString:@""] ||  [value isEqualToString:@"<null>"]))) ? YES : NO

像这样使用：

switch (rowtype) {
case PhoneRow:
{

    NSString *name = [NSString new];
     if (!IS_EMPTY(self.ecpInfo[@"Name"])) {
        name =  self.ecpInfo[@"Name”];                  
     }else{
        name = @“”;
     }

    cell = [self.tableView dequeueReusableCellWithIdentifier:reusableIdentifierNormalCell];
    cell.titleLabel.text = [NSString stringWithFormat:NSLocalizedString(@"Call %@", nil), name];
    cell.subtitleLabel.text = phoneNumber;
    cell.iconImageView.image = [UIImage imageNamed:@"TelephoneIcon"];
    cell.tag = ECPDetails_RowTagsStart + rowtype;
}

获取<null>值而不是空字符串

1 个答案: