Question

Python非常生疏，我希望按如下方式排序和打印2D数组。使用studentName和studentScore填充2D字典。循环并向字典添加新项目。我添加了studentName和studentScore作为示例。我想按studentName排序和打印dataSet ......但不确定如何。任何帮助都一如既往地受到赞赏......

dataSet = {}
position = len(dataSet)
studentName = "Derek"
studentScore = "80%"
dataSet.update({position : {"studentName": studentName, "Score": studentScore }})

我希望输出类似......

Student: Derek -- Score: 80%

当然，循环遍历dataSet中的每个项目

目前使用此...但是格式化为对象并且非常难看！

def viewScores(dataSet):
 for x in dataSet:
    for y in dataSet[x]:
        print (y,':',dataSet[x][y])

Answer 1

你应该检查python中词典的用法......你的问题可以这样解决：

def viewScores(dataSet):
 for student in sorted(dataSet.keys()):
    print ("{}: {}".format(student, dataSet[student]))


dataSet = {}
studentName = "Derek"
studentScore = "80%"
dataSet[studentName] = studentScore 
dataSet["Zyline"] = "99%"

print(dataSet) # just to show it works (and it might be sorted in reverse order)

viewScores(dataSet)

此外，我建议将分数存储为数字而不是字符串，并仅在打印声明中添加百分号。

根据您的新要求（重复名称），我会这样解决：

def viewScores(dataSet):
    for student in sorted(dataSet,  key=lambda x: x["studentName"]):
        print ("Student: {} -- Score {}%".format(student["studentName"], student["studentScore"]))


dataSet = []
studentID = 7
studentName = "Derek"
studentScore = 80
dataSet.append({"studentName": studentName, "studentScore": studentScore, "id": studentID}) 
dataSet.append({"studentName": "Zyline", "studentScore": 99, "id": 42})

print(dataSet) # just to show it works (and it might be sorted in reverse order)

viewScores(dataSet)

Answer 2

这是另一种可能的解决方案，按名称排序然后得分。正如所建议的那样，将分数存储为整数更有意义，因为这样可以更容易排序。

def viewScores(dataSet):
    entries = sorted([(dataSet[entry]['studentName'], dataSet[entry]['Score']) for entry in dataSet])

    for name, score in entries:
        print('Student: {} -- Score: {}%'.format(name, score))

dataSet = {}
position = len(dataSet)
studentName = "Derek"
studentScore = 80
dataSet.update({position : {"studentName": studentName, "Score": studentScore }})

position = len(dataSet)
studentName = "Andrew"
studentScore = 90

dataSet.update({position : {"studentName": studentName, "Score": studentScore }})
position = len(dataSet)
studentName = "Andrew"
studentScore = 9
dataSet.update({position : {"studentName": studentName, "Score": studentScore }})

viewScores(dataSet)

对于此示例，它将显示以下输出：

Student: Andrew -- Score: 9%
Student: Andrew -- Score: 90%
Student: Derek -- Score: 80%

Answer 3

首先，您应该使用.values()获取字典的值。

然后，您可以轻松访问每个studentName和studentScore。我使用了list comprehension

最后，使用sorted()对值进行排序。

valuesDict = dataSet.values()
valuesTuple = [(v["studentName"], v["Score"]) for v in valuesDict]
sortedValues = sorted(valuesTuple)

for student, score in sortedValues:
    print "Student: %s -- Score: %s" % (student, score)

在Python中对2D字典进行排序

3 个答案: