所以基本上我要做的就是进行第一次网络通话。如果被调用的RESTful Web服务返回1,则进行第二次网络调用。如果Web服务返回0,则不进行第二次网络呼叫。
这是我的代码
final ApiInterface apiInterface=restAdapter.create(ApiInterface.class);
apiInterface.submitDataToAnalyze("dataToAnalyze","852741963",1,"123","lalala","2015-11-20")
.flatMap(new Func1<BasicResponse, Observable<?>>() {
@Override
public Observable<?> call(BasicResponse basicResponse) {
if (basicResponse.getResult() == 1){
return apiInterface.getSuggestion("dataToAnalyze","852741963",1,"123","lalala","2015-11-20");
}else{
return 0; //error
}
}
}).subscribeOn(Schedulers.io()).observeOn(AndroidSchedulers.mainThread());
显然上面的代码是错误的,因为它应该总是返回Observable。那么,如果第一个网络调用返回0,我的代码应该怎么写?
答案 0 :(得分:1)
我认为最佳做法是返回Observable.error(new Throwable("..."))
取自javadoc:
/**
* Returns an Observable that invokes an {@link Observer}'s {@link Observer#onError onError} method when the
* Observer subscribes to it.
* <p>
* <img width="640" height="190" src="https://raw.github.com/wiki/ReactiveX/RxJava/images/rx-operators/error.png" alt="">
* <dl>
* <dt><b>Scheduler:</b></dt>
* <dd>{@code error} does not operate by default on a particular {@link Scheduler}.</dd>
* </dl>
*
* @param exception
* the particular Throwable to pass to {@link Observer#onError onError}
* @param <T>
* the type of the items (ostensibly) emitted by the Observable
* @return an Observable that invokes the {@link Observer}'s {@link Observer#onError onError} method when
* the Observer subscribes to it
* @see <a href="http://reactivex.io/documentation/operators/empty-never-throw.html">ReactiveX operators documentation: Throw</a>
*/