我的错误是
更新时出错:您的SQL语法出错;检查 手册,对应右边的MySQL服务器版本 在第1行“1”附近使用的语法
请记下在没有错误的情况下没有错误在帖子中我检查了每一位..更新查询导致该错误。我尝试了很多次但没有解决。提前致谢。
<?php
include('db.php');
session_start();
if(isset($_POST['update']))
{
$fname = mysql_real_escape_string($_POST['fname'], $con1);
$lname = mysql_real_escape_string($_POST['lname'], $con1);
$phone = mysql_real_escape_string($_POST['phone'], $con1);
$zip = mysql_real_escape_string($_POST['zip'], $con1);
$city = mysql_real_escape_string($_POST['city'], $con1);
$country = mysql_real_escape_string($_POST['country'], $con1);
$userId = $_SESSION['userID'];
$strSQL = mysql_query("SELECT * FROM sarah_cloudRecord.user_info WHERE userId = '$userId'" , $con1);
//$Results = mysql_fetch_array($strSQL);
$numrows = mysql_num_rows($strSQL);
if($numrows != 0)
{
while ($row = mysql_fetch_assoc($strSQL))
{
$dblname = $row['lastName'];
$dbfname = $row['firstName'];
$dbphone = $row['phone'];
$dbzip = $row['zipCode'];
$dbcity = $row['city'];
$dbcountry = $row['country'];
if ($fname != $dbfname || $fname == $dbfname)
{
$newfName = $fname;
}
if ($lname != $dblname || $lname == $dblname)
{
$newlName = $lname;
}
if ($phone != $dbphone || $phone == $dbphone)
{
$newPhone = $phone;
}
if ($zip != $dbzip || $zip == $dbzip)
{
$newZip = $zip;
}
if ($city != $dbcity || $city == $dbcity)
{
$newCity = $city;
}
if ($country != $dbcountry || $country == $dbcountry)
{
$newCountry = $country;
}
}
$updateSQL = mysql_query("UPDATE sarah_cloudRecord.user_info SET firstName = '$newfName', lastName = '$newlName', phone = '$newPhone', city = '$newCity', zipCode = '$newZip', country = '$newCountry' WHERE userId = '$userId'", $con1);
if (mysql_query($updateSQL, $con1))
{
echo "Update Successfully!";
}
else {
echo "Error while updating: " . mysql_error($con1);
}
}
else {
echo "no records found";
}
}
else
{
?>
<script type="text/javascript">
window.location = "http://dev.metawarez.com/cloud/login.php";
</script>
<?php
}
?>
答案 0 :(得分:1)
两次使用mysql_query
。您将更新查询更改为
$updateSQL = "UPDATE sarah_cloudRecord.user_info SET firstName = '$newfName', lastName = '$newlName', phone = '$newPhone', city = '$newCity', zipCode = '$newZip', country = '$newCountry' WHERE userId = '$userId'";
if (mysql_query($updateSQL, $con1))
注意: - 不推荐使用mysql而是使用mysqli或pdo
答案 1 :(得分:1)
您正在查询UPDATE的回复,即1来自哪里。
http://php.net/manual/de/function.mysql-query.php
$updateSQL = mysql_query("UPDATE sarah_cloudRecord.user_info SET firstName = '$newfName', lastName = '$newlName', phone = '$newPhone', city = '$newCity', zipCode = '$newZip', country = '$newCountry' WHERE userId = '$userId'", $con1);
if ($updateSQL !== false)
{
echo "Update Successfully!";
} else {
echo "Error while updating: " . mysql_error($con1);
}