Question

我一直收到错误未定义的引用'vtable for Producer' 为我的子类生产者：

#include "Producer.h"

Producer::Producer (unsigned int ID, int age1, std::string name1,
        char gender1, std::string jobDescription1)
        {IDNumber = ID; age = age1; name = name1;
        jobDescription = jobDescription1; gender = gender1;}

void SetJobDescription(std::string description){}

void PrintPersonnel(){cout<<"";}

Producer::~Producer(){}

父母是：

#include <string>
#include <iostream>


class Personnel{
protected:
    unsigned int IDNumber;
    int age;
    std::string jobDescription;
    std::string name;
    char gender;
public:

    virtual void PrintPersonnel() = 0;

    unsigned int GetID();

    int GetAge();

    std::string Getname();

    std::string GetjobDescription();

    char GetGender();

    virtual ~Personnel();

};

// Personel.cpp

#include "Personnel.h"
unsigned int Personnel::GetID(){return IDNumber;}

int Personnel::GetAge(){return age;}

std::string Personnel::Getname(){return name;}

std::string Personnel::GetjobDescription(){return jobDescription;}

char Personnel::GetGender(){return gender;}

Personnel::~Personnel(){}

它具有纯虚函数。为什么我不能实现子类Producer？

非常感谢。

Answer 1

代码中的问题是您忘记了一个成员函数的范围。试试：

void Producer::PrintPersonnel(){cout<<"";} // Producer:: was missing
                                           // so you were defining a global function instead
                                           // of a member function.

请注意，您对SetJobDescription()的定义存在类似问题。由于它不是虚函数，它只会引导您进入未定义的引用。

如果它仍然不起作用，那么您应该在评论中建议的某个地方定义~Personnel()。

C ++类型未定义对`vtable for Producer'的引用

1 个答案: