Question

我想在随机位置创建10个ImageViews，我希望它们是相同的，我尝试使用ImageView[]，我得到了屏幕尺寸（宽度和高度）并为每个创建了随机位置ImageView（在屏幕大小范围内）。有些ImageViews超出范围，因为有时我会看到7,8 ImageViews。这是我的代码：

 ImageView ball[], you;
    int layoutwidth, layoutheight;
    Random rand = new Random();
    RelativeLayout rlt;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        rlt = (RelativeLayout) findViewById(R.id.rlt);
        you = (ImageView) findViewById(R.id.imageView);
        Display display = getWindowManager().getDefaultDisplay();
        Point size = new Point();
        display.getSize(size);
        layoutwidth = size.x;
        layoutheight = size.y;
        ball = new ImageView[11];
        for (int i = 0; i < 10; i++) {
            ball[i] = new ImageView(this);
            ball[i].setTag(i);
            ball[i].setBackgroundResource(R.mipmap.ball);
            int randomx = rand.nextInt(layoutwidth+1);
            int randomy = rand.nextInt(layoutheight+1);
            ball[i].setX(randomx);
            ball[i].setY(randomy);
            rlt.addView(ball[i]);
        }
    }

如何根据需要使代码正常工作？

Answer 1

您可以尝试替换此

int randomx = rand.nextInt(layoutwidth+1);
int randomy = rand.nextInt(layoutheight+1);
ball[i].setX(randomx);
ball[i].setY(randomy);
rlt.addView(ball[i]);

与

int randomx = rand.nextInt(layoutwidth+1-widthOfImageView);
int randomy = rand.nextInt(layoutheight+1-heightOfImageView);
rlt.addView(ball[i]);   
ball[i].setTranslationX(randomx);
ball[i].setTranslationY(randomy);

其中 widthOfImageView，heightOfImageView 是imageview＆＃39;的宽度＆amp;高度

试图使ImageView数组保持在屏幕范围内

1 个答案: