Question

我无法在基于Django类的视图中访问当前登录的用户：

models.py：

class Userproject(models.Model):
class Meta:
    verbose_name = u'pp'
    verbose_name_plural = u'pps'

user = models.ForeignKey(settings.AUTH_USER_MODEL, related_name="project", verbose_name=_("Владелец проекта"))
#user = models.ForeignKey(User, unique=True)

name = models.TextField(u'Название проекта', unique=True)
date_created = models.DateTimeField(u'Дата создания', default=datetime.now(), db_index=True)
date_until = models.DateTimeField(u'Оплачен по', default=datetime.now(), db_index=True)

views.py：

@login_required
class UserprojectList(ListView):
    context_object_name = 'userproject_list'
    queryset = Userproject.objects.filter(user=self.request.user)
    template_name = 'userproject_list.html'

当我导航到url时，我看到错误： 姓名＆＃39; self＆＃39;未定义

如果我将self.request.user更改为request.user 错误是：名称＆＃39;请求＆＃39;未定义

请注意，没有用户过滤视图正在运行并显示数据 django 1.8.5

Answer 1

您可以覆盖get_queryset：

@login_required
class UserprojectList(ListView):
    context_object_name = 'userproject_list'
    template_name = 'userproject_list.html'
    def get_queryset(self):
        return Userproject.objects.filter(user=self.request.user)

同样你不能在类上使用装饰器，所以你必须写这样的东西：

from django.utils.decorators import method_decorator

class UserprojectList(ListView):
    context_object_name = 'userproject_list'
    template_name = 'userproject_list.html'

    @method_decorator(login_required)
    def dispatch(self, *args, **kwargs):
        return super(UserprojectList, self).dispatch(*args, **kwargs)

    def get_queryset(self):
        return Userproject.objects.filter(user=self.request.user)

Answer 2

我会尝试在__init__方法中执行此操作：

@login_required
class UserprojectList(ListView):
    context_object_name = 'userproject_list'
    template_name = 'userproject_list.html'
    def __init__(self, *args, **kwargs):
        super(UserprojectList, self).__init__(*args, **kwargs)
        self.queryset = Userproject.objects.filter(user=self.request.user)

Answer 3

我认为在基于类的视图中，您需要覆盖get_queryset（）方法，以便能够访问附加到视图实例的self.request对象，而不是在类级别执行此操作。 Classy Class-Based Views网站提供了更多信息：http://ccbv.co.uk/projects/Django/1.8/django.views.generic.list/ListView/

Answer 4

@pythad的答案是正确的。但是在Django 1.9+上，您可以使用django.contrib.auth.mixins.LoginRequiredMixin代替旧的@login_required装饰器，而不是dispatch方法。

from django.contrib.auth.mixins import LoginRequiredMixin

class UserprojectList(LoginRequiredMixin, ListView):
    context_object_name = 'userproject_list'
    template_name = 'userproject_list.html'

    def get_queryset(self):
        return Userproject.objects.filter(user=self.request.user)

如何在基于Django类的视图中访问当前用户

4 个答案: