我的插入方法有问题,因为某些原因我最终得到了无限循环。这是我的结构:
mysql> SELECT LPAD('hi',4,'??');
-> '??hi'
mysql> SELECT LPAD(123, 5,'0');
-> 00123
这是我的插入方法:
#Define SW_HIDE 0
#Define SW_NORMAL 1
#Define SW_SHOWMINIMIZED 2
#Define SW_SHOWMAXIMIZED 3
Local lcResult
lcResult = ShellExec('C:\Windows\System32\restart.bat', '', 'C:\Windows\System32', SW_NORMAL)
If !Empty(m.lcResult) && error
Messagebox(m.lcResult)
Endif
Function ShellExec
Lparameters tcExecutable,tcParams,tcWorkingDir,tnShowType,tcOperation
Declare Long ShellExecute In "shell32.dll" ;
long HWnd, String lpszOp, ;
string lpszFile, String lpszParams, ;
string lpszDir, Long nShowCmd
tcOperation = Iif(Empty(m.tcOperation), 'Open', m.tcOperation)
tcExecutable = Iif(Empty(m.tcExecutable), '', m.tcExecutable)
tcParams = Iif(Empty(m.tcParams), '', m.tcParams)
tcWorkingDir = Iif(Empty(m.tcWorkingDir), '', m.tcWorkingDir)
tnShowType = Iif(Type('m.tnShowType') # 'N', SW_SHOWNORMAL, m.tnShowType)
Local lnResult, lcError
lcError = ''
lnResult = ShellExecute(0,m.tcOperation,m.tcExecutable,m.tcParams,m.tcWorkingDir,m.tnShowType)
If !( m.lnResult > 32 ) && Error
lcError = GetShExecErrorMsg(m.lnResult)
Endif
Return m.lcError
Endfunc
Function GetShExecErrorMsg
Lparameters tnErrNum
Local Array aErrors[1]
Local lcMessage, lcErrors,lnErrors,ix
TEXT to m.lcErrors noshow
0,The operating system is out of memory or resources. \n
2,The specified file was not found. \n
3,The specified path was not found. \n
11,The .exe file is invalid (non-Win32® .exe or error in .exe image). \n
5,The operating system denied access to the specified file. \n
27,The file name association is incomplete or invalid. \n
30,The DDE transaction could not be completed because
other DDE transactions were being processed. \n
29,The DDE transaction failed. \n
28,The DDE transaction could not be completed because the request timed out. \n
32,The specified dynamic-link library was not found. \n
31,There is no application associated with the given file name extension.
This error will also be returned if you attempt to print a file that is not printable. \n
8,There was not enough memory to complete the operation. \n
26,A sharing violation occurred. \n
ENDTEXT
Clear
lnErrors = Alines(aErrors,m.lcErrors,.T.,'\n')
For ix=1 To m.lnErrors
If ( Val(Chrtran(Left(aErrors[m.ix],;
At(',',aErrors[m.ix])-1),Chr(13)+Chr(10),'')) = m.tnErrNum )
lcMessage = Substr(aErrors[m.ix],At(',',aErrors[m.ix])+1)
Exit
Endif
Endfor
If Empty(m.lcMessage)
lcMessage = 'An unspecified error occurred.'
Endif
Return m.lcMessage
Endfunc
我在这里发现了类似的问题:C - Inserting into linked list in ascending order但它并没有真正帮助我。
答案 0 :(得分:3)
insert
的第一个参数是指针。但是你需要一个指针指针(struct List **first
)。
如果列表为空,则将 VALUE NULL传递给函数(方法内的变量first
的值为NULL)。然后为其分配一个新的malloced值并返回。呼叫方的变量没有改变,你的记忆泄露了。
当您传递指针的指针时,变量first
保存调用方法的变量的地址。这样,您可以重新分配它的价值。
指针,指针指针,返回函数指针的函数数组的指针......这就是C的有趣部分;)