Question

我有这个脚本来生成一个随机数，但我需要它是唯一的。我尝试使用while循环来检查它是否已经存在于数据库中，但它对我不起作用。

 $numbers = range(6, 1);
    $random = '';
    shuffle($numbers);
    foreach ($numbers as $number) {
        $random.= $number;
    }

这是我尝试使用的代码

    var stop_cycle = 0;

while (!stop_cycle) {
$numbers = range(6, 1);
    $random = '';
    shuffle($numbers);
    foreach ($numbers as $number) {
        $random.= $number;
    }
$db->query("SELECT upload_ID FROM uploads WHERE upload_ID = ".$random);

// check if query returns any result
if(mysql_affected_rows() == 0)  {

// DOING STUFF

// end cycle
 stop_cycle=1;
}

}

Answer 1

你几乎拥有它。问题是除非页面已刷新，否则您无法生成新号码。我创建了一个函数，脚本可以继续调用，直到找到没有结果的数据库条目。

<?php
function generateNumber(){
$numbers = range(6, 1);
$random = '';
shuffle($numbers);
foreach ($numbers as $number) {
    $random.= $number;
}
return $random;
}

// start the do loop. If the query returns more than 0 results, it will 
// pick up another number and attempt again.
do { 
    $number = generateNumber();
    $mysqli->query("SELECT upload_ID FROM uploads WHERE upload_ID = $number");
}while(mysqli_num_rows > 0);

?>

检查它是否存在于mysql

1 个答案: