Question

我正在尝试使用服务器端处理来填充jquery数据表。在php中，我使用mysql连接查询从两个表中获取数据。

我的查询如下：

$sQuery = "SELECT SQL_CALC_FOUND_ROWS u.user_id 
                    , CONCAT(u.first_name, ' ', u.last_name)
                    , u.gender
                    , CONCAT(a.suburb, ', ', a.zip_code)
                    , u.date_registered
            FROM users u 
            INNER JOIN user_addresses a ON a.user_id = u.user_id AND a.address_type = 1 ".$sWhere.$sOrder.$sLimit;

列数组是这样的：

$aColumns = array (
                    "u.user_id", 
                    "CONCAT(u.first_name, ' ', u.last_name)", 
                    "u.gender", 
                    "CONCAT(a.suburb, ', ', a.zip_code)", 
                    "u.date_registered"
                  );

我的问题是它的显示数据仅适用于第2和第4列。它为其他列提供了null个值。

{
 "sEcho": 1,
 "iTotalRecords": "7",
 "iTotalDisplayRecords": "7",
 "aaData": [
     [null, "Tharanga Kumara", null, "Wanniassa
, 2903", null],
     [null, "dsfadsf fdaf", null, "Ashford, 5035", null],
     [null, "fdafa dfdaf", null, "Wanniassa, 2903", null],
     [null, "Dilani Kumari", null, "dfdaf, 34234", null],
     [null, "Kamal Maduranga ", null, "Wanniassa, 2903", null],
     [null, "Sampath Gunathilaka", null, "Eastern Suburbs Mc, 2004", null],
     [null, "Kasun Sandaruwan", null, "Wanniassa, 2903", null]
 ]

}

更新数据表代码：

.DataTable({
  bAutoWidth: false,    
  "bProcessing": true,
  "bServerSide": true,
  "sAjaxSource": "includes/process_customer_datatable.php",

  "aoColumnDefs":  [{ 
                      "aTargets": [0],
                      "bSortable": false,
                      //"sTitle": "ip", 
                      "sClass": "center",
                      "mRender": function (data, type, full) {
                         return '<label class="pos-rel">' + 
                                  '<input class="custom" type="checkbox">' + 
                                '</label>';
                      }
                    },
                    {
                     "aTargets": [5],    //Delete column
                     "mData": "0",  
                     "mRender": function (data, type, full) {
                       return '<a  href=' + 'index.php?customer=' + data + '>Delete</a>';
                     }                    
                    }
                  ],



  // "aoColumns": [
  //   { "bSortable": false },
  //   null, 
  //   null,
  //   null,  
  //   null, 
  //   null, 
  //   { "bSortable": false }, 
  // ],
  "aaSorting": [],

});

有谁能告诉我这是什么问题？希望有人可以帮助我。

Answer 1

您可以对从PHP返回的对象进行字符串化。使用带有空字符串的正则表达式替换空值，然后将字符串解析回JSON对象。

此处示例：

http://jsfiddle.net/yhoLboLr/

import cats.state.State
import cats.std.function._, cats.std.list._
import cats.syntax.traverse._

abstract class DepthFirstState[E, S] {
  def build(elem: E): State[S, List[E]]

  def go(start: E): State[S, List[E]] = for {
    xs <- build(start)
    ys <- xs.traverseU(go)
  } yield start :: ys.flatten
}

class RangeSearchState extends DepthFirstState[Int, Int] {
  def build(elem: Int): State[Int, List[Int]] =
    State.get[Int].map(limit => if (elem < limit) List(elem + 1) else Nil)
}

val (state, result) = (new RangeSearchState).go(1).run(10000).run

来自服务器端处理的jquery数据的空值

1 个答案: