我想编写一个关于ascii的程序,它会给你char,并要求你输入小数,它只能选择字符或全部。有很多错误,我不知道如何解决它们。请帮我。
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
void ALL();
void character();
void ask();
int main(){
ask();
return 0;
}
void ask(){
char type;
char character;
char all;
cout<<"You can choose all or only character\ttype in(all / character)"<<endl;
cin>>type;
do{
if(type=='character'){
character();
}else if(type=='all'){
ALL();
}else{
ask();
}
}while(1);
}
void ALL(){
int a, b;
do{
srand((unsigned)time(NULL));
a=rand() %255 + 1;
b=a;
cout<<"What is the ascii code of "<<(char) a<<" ?"<<endl;
cin>>b;
if(b==a){
cout<<"You are RIGHT!!!"<<endl;
cout<<"----------------------------------\n----------------------------------"<<endl;
}else{
cout<<"You are WRONG!!!"<<endl;
cout<<"The ascii code of "<<(char) a<<" is "<<a<<endl;
cout<<"----------------------------------\n----------------------------------"<<endl;
}
}while(1);
}
void character(){
int a, b, c;
do{
srand((unsigned)time(NULL));
c = rand() % 2;
if(c==1){
b = rand() % 26 + 65;
}else if(c==2){
b = rand() % 26 + 97;
}
b=a;
cout<<"What is the ascii code of "<<(char) a<<" ?"<<endl;
cin>>b;
if(b==a){
cout<<"You are RIGHT!!!"<<endl;
cout<<"----------------------------------\n----------------------------------"<<endl;
}else{
cout<<"You are WRONG!!!"<<endl;
cout<<"The ascii code of "<<(char) a<<" is "<<a<<endl;
cout<<"----------------------------------\n----------------------------------"<<endl;
}
}while(1);
}
Tt在底部[编译器]
显示了这一点↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓ ↓↓↓↓↓↓↓
24 11 C:\ Users \ Thomas \ Desktop \ program \ C ++ \ ASCII_2.cpp [警告]字符常量太长,其类型[默认启用]
26 17 C:\ Users \ Thomas \ Desktop \ program \ C ++ \ ASCII_2.cpp [警告]多字符字符常量[-Wmultichar]
C:\ Users \ Thomas \ Desktop \ program \ C ++ \ ASCII_2.cpp in function&#39; void ask()&#39;:
25 13 C:\ Users \ Thomas \ Desktop \ program \ C ++ \ ASCII_2.cpp [错误]&#39;字符&#39;不能用作函数
答案 0 :(得分:1)
将char type;
更改为string type;
..
此外,在您要比较type == 'character'
的区域,您必须将其更改为
if(type == "character")
{
...
}
同样改变其他比较。
OR
如果你只想在这里使用char ......
输入c
或a
并将条件更改为
if(type == 'c')
{
...
}