Question

我正在处理一个SQL查询。

表名：employees。

我希望在SQL中使用其员工姓名获取MAX和MIN sal。

我知道如何处理MAX或MIN。但是我们怎样才能在一个查询中做到这一点？

我需要一个单行输出，如下所示：

e1.name AS MaxName, MAX(e1.sal) AS MaxSalary, e2.name AS MinName, MIN(e2.sal) AS MinSalary

Answer 1

两种方式：

使用 Analytic 功能：

SQL> WITH DATA AS
  2    ( SELECT MIN(sal) min_sal, MAX(sal) max_sal FROM emp
  3    )
  4  SELECT
  5    (SELECT e.ename FROM DATA t, emp e WHERE e.sal = t.min_sal AND ROWNUM =1
  6    ) min_name,
  7    (SELECT t.min_sal FROM DATA t, emp e WHERE e.sal = t.min_sal AND ROWNUM =1
  8   ) min_sal,
  9    (SELECT e.ename FROM DATA t, emp e WHERE e.sal = t.max_sal AND ROWNUM =1
 10   ) max_name,
 11    (SELECT t.max_sal FROM DATA t, emp e WHERE e.sal = t.max_sal AND ROWNUM =1
 12   ) max_sal
 13     FROM dual;

MIN_NAME      MIN_SAL MAX_NAME      MAX_SAL
---------- ---------- ---------- ----------
SMITH             800 KING             5000

使用内嵌视图：

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Answer 2

在单个选择中：

SELECT  MIN( salary ) AS MinSalary,
        MIN( name ) KEEP ( DENSE_RANK FIRST ORDER BY salary ASC ) AS MinName,
        MAX( Salary ) AS MaxSalary,
        MAX( name ) KEEP ( DENSE_RANK LAST ORDER BY salary ASC ) AS MaxName
FROM    Employees;

Answer 3

以下解决方案适用于MySQL，这是您在发布问题时最初使用的标记之一。

您可以对自己执行CROSS JOIN employees表，以查找最大名称/工资，并查询最小名称/工资。

SELECT e1.name AS MaxName, MAX(e1.sal) AS MaxSalary,
    e2.name AS MinName, MIN(e2.sal) AS MinSalary
FROM employees e1 CROSS JOIN employees e2

点击下面的链接查看正在运行的演示。我实际上包括名称/工资对，但如果你不想要它们，你可以删除它们。

SQLFiddle

Answer 4

尝试类似：

select max(sal), min(sal), employee_id 
from employees
group by employee_id;

之后，您可以加入它以获取名称。也许你也可以按姓名和身份分组。

Answer 5

假设您使用的是Oracle，请尝试此操作。首先，我们按升序和降序获取rownumber，然后进行交叉连接。

with employee(id,name,sal) as
(select 1,'a',1000 from dual union all
select 3,'c',1500 from dual union all
select 2,'b',2000 from dual)   --temp table to recreate the scenario
, enew as(
select e.*,row_number() over (order by sal) as salasc,row_number() over (order by sal desc) as saldesc from employee e
) --temp table to find the rownumber in ascending and descending order
--original query
select * from (select id as minsalid,name as minsalempname,sal as minsal from enew
where salasc=1)
cross join
(select id as maxsalemp,name as maxsalempname,sal as maxsal from enew
where saldesc=1)

Max和Min sal在一个查询中包含员工姓名

5 个答案: