我有一个程序，我写的是应该加密和解密一组预定的字符串。提供了主类，我必须编写依赖项，但是我的对象没有被正确调用，从而产生了大量的编译时错误。两个依赖项都可以自行编译，所以我必须在类之间的接口中犯了错误。它有相当多的代码，所以这里是一个pastebin链接：
编辑：现在我遇到了重大的逻辑错误。我知道它在加密器中，也可能是解密器，但我之前已经使用过解密器，我在这里做的只是将X从固定值改为难度。
编辑2：现在已经修复了randChar，现在我只需要弄清楚我的en / decrypt循环中有什么问题。
这是我的新错误/输出：
==============================
Simulating difficulty level 0:
Encrypting String: kitty ...
Encrypted as: xvrdsoyttik
Decrypting String: xvrdsoyttik ...
Decrypted as: kkkkkkkkkkkk
Fail!
==============================
Simulating difficulty level 1:
Encrypting String: test string ...
Encrypted as: gqpyqfdqqwvcqnirts tset
Decrypting String: gqpyqfdqqwvcqnirts tset ...
Decrypted as: test strinqcvwqqdfqypqg
Fail!
==============================
Simulating difficulty level 2:
Encrypting String: Agent: James Bond ...
Encrypted as: dnjomBe bsveimqaiJa :tnegA
Decrypting String: dnjomBe bsveimqaiJa :tnegA ...
Decrypted as: Aet James Bon
Fail!
==============================
加密器：
/**
encryptString encrypts the string, as well as stores the original for later use
@param str The string to be encrypted
@return encrypted The encrypted string
*/
public String encryptString(String str)
{
int length = str.length();
origStr = str;
int x = diff;
StringBuilder codeRev = new StringBuilder(str).reverse();
for (int pos = 0; pos <= length; pos++)
{
if (x <= length + diff) //removed
{
codeRev.insert(x, randomLetter());
}
x = x + diff + 1;
}
encryptedStr = codeRev.toString();
return(codeRev).toString();
}
解密：
/**
decryptString decrypts the code based on using the difficulty as the increment.
@param code The encrypted string
@return decrypted The decrypted string
*/
public String decryptString(String code)
{
int length = code.length();
int x = 0; //to 1
encryptedStr = code;
String codeRev = new StringBuilder(code).reverse().toString();
StringBuilder decrypted = new StringBuilder();
for (int pos = 0; pos <= length; pos++)
{
if (x < length) //removed <=
{
decrypted.append(codeRev.charAt(x));
}
x = x + diff;
}
decryptedStr = decrypted.toString();
return(decrypted).toString();
}
随机字符制作者：
/**
Generates a random letter
@return letter The random letter
*/
public char randomLetter()
{
Random ranChar = new Random();
char cr = (char)(ranChar.nextInt(26)+ 'a');
return cr;
}