是否可以在Javascript的switch块中使用来自switch块的响应来使用if / else语句?以下是我尝试这样做的方法。这是一个CodeAcademy项目,您必须使用切换块和条件语句编写自己的冒险。
var user = prompt("You awake; dazed, blurred and lost. What do you do?").toLowerCase()
var day = 0;
switch (user) {
case "look at the time":
console.log("Good start, how long was I out for?");
if (
case "look at the time" && day === 0) {
console.log("it's only been a few hours, but time is still ticking");
day++
} else if (day > 0) {
console.log("it's been " + day + "s! Will I make it out of here");
day++
}
break;
case "figure out where I am":
console.log("Yeah, how did I end up here in the first place?");
if (
case "figure out where I am" && day === 0) {
console.log("This is a good checkpoint");
day++
}
break;
case 'run':
console.log("Dry your eyes, find a direction, and hope for the best");
break;
case 'give up':
console.log('Thanks for trying, have fun, where ever you are...');
break;
default:
console.log("you fall back unconscious, hoping to wake again");
day++;
if (
default) {
return user;
}
if (
case 'run' ||
case 'give up') {
console.log("It would have ended up coming down to this option anyway");
}
}
答案 0 :(得分:0)
如果您进行更改以停止在case
语句中使用单词if
,它将会起作用,例如它应该看起来像这样执行与user
变量的比较案例陈述:
if (user === "look at the time" && day === 0) {
console.log("it's only been a few hours, but time is still ticking");
day++
} else if (day > 0) {
console.log("it's been " + day + "s! Will I make it out of here");
day++
}
在这种情况下,比较user === "look at the time"
是多余的,因为该逻辑已在switch语句本身中进行评估。我刚刚将其包含在内,以便您可以看到如何与user
变量进行比较,但可以将其完全排除,并在此情况下具有相同的效果。