Question

如果我的问题听起来很愚蠢，那么我很擅长编程。我试图从MySQL数据库中列出行。我的要求是为部门下的每个指定连续处理每个项目的计数器。例如：我的每一行都有部门名称和名称，对应MySQL DB中的部门。我试图在下面演示MyMSQL表的结构。我想要获得的输出是以下格式

Department          Desig1              Desig2              Desig3
==========          ======              ======              ======
IT                  Director            Manager             Asst. Mgr
Finance             Finance Contr       Finance Mgr         Chartd Acct.
Admin               CEO                 Gen. Mgr.           Mgr

这就是我期待的输出方式。

IT
1 Director
2 Manager
3 Asst. Manager

Finance
1 Finance Controller
2 Finance Manager
3 Charted Accountant

Administration
1 CEO
2 General Manager
3 Manager

我尝试使用以下代码从MySQL检索数据，无法以我正在寻找的格式获得结果。尝试在同一个循环中添加一个增量，认为它可能会有所帮助，但我错了。请指教。

注意：我正在使用bootstrap进行背景设计。

<?php
    $servername = "localhost";
    $username = "username";
    $password = "password";
    $dbname = "dbname";

    // Create connection
    $conn = new mysqli($servername, $username, $password, $dbname);

    // Check connection
    if ($conn->connect_error) 
    {
        die("Connection failed: " . $conn->connect_error);
    }

    $sql = "SELECT Dept, Desig1, Desig2, Desig3 FROM comdept";
    $result = $conn->query($sql);

    if ($result->num_rows > 0) 
    {
        while ($row = mysqli_fetch_assoc($result)) 
        {
            i=0;
            echo "<div class='panel-heading'><div class='panel-title'><strong>".$row["Dept"]."</strong></div></div><table class='table table-bordered table-hover'><thead><tr><th class='col-sm-1'>SL</th><th>Designations</th></tr></thead><tbody><tr><td>".i++."</td><td>".$row["Desig1"]."</td></tr><tr><td>".i++."</td><td>".$row["Desig2"]."</td></tr><tr><td>".i++.".</td><td>".$row["Desig3"]."</td></tr></tbody></table>";
        }
    }
    else
    {
        echo "0 results";
    }
?>

Answer 1

请尝试使用此格式：

$i=0;
echo "<table class='table table-bordered table-hover'>";
while ($row = mysqli_fetch_assoc($result)) {

    echo "<tr><td colspan=2>".$row["Dept"]."</td></tr>";
    echo "<tr><td>".$i++."</td><td>".$row["Desig1"]."</td></tr>";
    echo "<tr><td>".$i++."</td><td>".$row["Desig2"]."</td></tr>";
    echo "<tr><td>".$i++."</td><td>".$row["Desig3"]."</td></tr>";
    echo "<tr><td colspan=2></td></tr>";

}
echo "</table>";

霍普这有帮助。

Answer 2

您查询时出现错误＆＃34; SELECT Dept，Desig1，Desig2，Desig3 FROM comdept＆＃34;列标题是＆＃34;部门＆＃34;而不是＆＃34;部门＆＃34; 这是相关的 `

echo $sql = "SELECT Department, Desig1, Desig2, Desig3 FROM comdept";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    echo "<table class='table table-bordered table-hover'>";
    while ($row = mysqli_fetch_assoc($result)) {

        echo "<tr><td colspan=2>".$row["Department"]."</td></tr>";
    echo "<tr><td>1</td><td>".$row["Desig1"]."</td></tr>";
    echo "<tr><td>2</td><td>".$row["Desig2"]."</td></tr>";
    echo "<tr><td>3</td><td>".$row["Desig3"]."</td></tr>";
    echo "<tr><td colspan=2></td></tr>";
        //$i=0;
    //echo "<div class='panel-heading'><div class='panel-title'><strong>".$row["Dept"]."</strong></div></div><table class='table table-bordered table-hover'><thead><tr><th class='col-sm-1'>SL</th><th>Designations</th></tr></thead><tbody><tr><td>".i++."</td><td>".$row["Desig1"]."</td></tr><tr><td>".i++."</td><td>".$row["Desig2"]."</td></tr><tr><td>".i++.".</td><td>".$row["Desig3"]."</td></tr></tbody></table>";
    }echo "</table>"; else{echo "0 results";}

`

如何在一行中显示MySQL的列，每个项目都有计数器

2 个答案: