Question

在对我的服务器执行GET请求时，我设置的.PHP文件只返回最新的JSON对象，而不是整个数组。我认为它被覆盖了数组，没有增加它，但我对PHP不太强大，可以指向正确的方向。

感谢您提前获得任何帮助，代码如下。

<?php
$result = mysql_query("SELECT * FROM books WHERE uni_year = '$uni_year' AND uni_course = '$uni_course'") or die(mysql_error());

if(!empty($result)) {
    if (mysql_num_rows($result) > 0) {

        $result = mysql_fetch_array($result);
       // $result = mysql_fetch_array($result);

       // while($row = mysql_fetch_array($result)){
        // temp array
        $books = array();
        $books["list_id"] = $result["list_id"];
        $books["book_title"] = $result["book_title"];
        $books["uni_course"] = $result["uni_course"];
        $books["uni_year"] = $result["uni_year"];
        $books["book_author"] = $result["book_author"];
        $books["book_price"] = $result["book_price"];
        $books["book_year"] = $result["book_year"];
        $books["isbn"] = $result["isbn"];
    //}
        // success
        $response["success"] = 1;

        // user node
        $response["books"] = array();

        array_push($response["books"], $books);

    } else {
        $response["success"] = 0;
        $response["message"] = "num of rows bigger than zero";
    }
} else {
        $response["success"] = 0;
        $response["message"] = "No product found";

        echo json_encode($response);
}


    echo json_encode($response);
} else {
    $response["success"] = 0;
    $response["message"] = "Required field(s) is missing";

    echo json_encode($response);
}
?>

Answer 1

您只从结果中获取第一条记录（$result = mysql_fetch_array($result);）。

您需要在循环中获取它们：

<?php
$result = mysql_query("SELECT * FROM books WHERE uni_year = '$uni_year' AND uni_course = '$uni_course'") or die(mysql_error());

if(!empty($result)) {
    if (mysql_num_rows($result) > 0) {
        $books = array();

        while($row = mysql_fetch_array($result)){
            $book = array();
            $book["list_id"] = $row["list_id"];
            $book["book_title"] = $row["book_title"];
            $book["uni_course"] = $row["uni_course"];
            $book["uni_year"] = $row["uni_year"];
            $book["book_author"] = $row["book_author"];
            $book["book_price"] = $row["book_price"];
            $book["book_year"] = $row["book_year"];
            $book["isbn"] = $row["isbn"];
            $books[] = $book;
        }
        // success
        $response["success"] = 1;

        // user node
        $response["books"] = $books;
    } else {
        $response["success"] = 0;
        $response["message"] = "num of rows bigger than zero";
    }
} else {
    $response["success"] = 0;
    $response["message"] = "No product found";
}


echo json_encode($response);

PHP文件只返回一个（最新的）JSON对象

1 个答案: