我使用此处提到的方法创建了启动画面:http://delphi.about.com/od/formsdialogs/a/splashscreen.htm
我需要在显示主窗体之前显示启动画面3秒钟。
请帮忙。感谢。
答案 0 :(得分:6)
项目内部文件:
program Project1;
uses
Forms,
Unit1 in 'Unit1.pas' {Form1},
uSplashScreen in 'uSplashScreen.pas' {frmSplashScreen};
{$R *.res}
begin
Application.Initialize;
Application.MainFormOnTaskbar := True;
frmSplashScreen := TfrmSplashScreen.Create(nil);
try
frmSplashScreen.Show;
// Create your application forms here
Application.CreateForm(TForm1, Form1);
while not frmSplashScreen.Completed do
Application.ProcessMessages;
frmSplashScreen.Hide;
finally
frmSplashScreen.Free;
end;
Application.Run;
end.
内部启动画面单元:
unit uSplashScreen;
interface
uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, ExtCtrls;
type
TfrmSplashScreen = class(TForm)
Timer1: TTimer;
procedure FormShow(Sender: TObject);
procedure Timer1Timer(Sender: TObject);
private
{ Private declarations }
public
Completed: Boolean;
end;
var
frmSplashScreen: TfrmSplashScreen;
implementation
{$R *.dfm}
procedure TfrmSplashScreen.FormShow(Sender: TObject);
begin
OnShow := nil;
Completed := False;
Timer1.Interval := 3000; // 3s minimum time to show splash screen
Timer1.Enabled := True;
end;
procedure TfrmSplashScreen.Timer1Timer(Sender: TObject);
begin
Timer1.Enabled := False;
Completed := True;
end;
end.
如果需要更多时间来创建应用程序的所有形式,启动屏幕将至少显示3秒或更长时间。
答案 1 :(得分:3)
要实现您想要的效果,您可以按照您提供的链接中描述的方法,并在启动屏幕的表单代码中放置一个计时器,该计时器在3秒后被触发并关闭表单。
主.dpr文件
var SplashScreen : TForm2;
begin
Application.Initialize;
Application.MainFormOnTaskbar := True;
SplashScreen := TForm2.Create(nil); // Creating with nil so this is not registered as main form
try
SplashScreen.ShowModal; // Blocking the execution for as long as this form is open
finally
SplashScreen .Free;
end;
Application.CreateForm(TForm1, Form1);
Application.Run;
在将作为“启动画面”的表单上添加计时器,以3000间隔启用(3s)
使用以下事件处理程序
procedure TForm2.Timer1Timer(Sender: TObject);
begin
Self.Close;
end;
答案 2 :(得分:1)
您应该使用计时器,其间隔设置为3000(3(s)* 1000(ms))。必须将Enabled设置为true。在Timer's-default-event上添加代码,用于显示主窗体。