Question

我想知道如何获取启用了自动换行的Tkinter Text小部件中的行数。

在此示例中，文本小部件中有3行：

from Tkinter import *

root = Tk()
text = Text(root, width = 12, height = 5, wrap = WORD)
text.insert(END, 'This is an example text.')
text.pack()

root.mainloop()

但是适用于非包装文本的方法，例如：

int(text_widget.index('end-1c').split('.')[0])

将返回1而不是3.是否有另一种方法可以正确计算包裹的行（并在我的示例中返回3）？

感谢您的帮助！

Answer 1

使用“缺失计数方法”的工作示例

打印

displaylines：3
行：1

from Tkinter import *

def count_monkeypatch(self, index1, index2, *args):
    args = [self._w, "count"] + ["-" + arg for arg in args] + [index1, index2]

    result = self.tk.call(*args)
    return result

Text.count = count_monkeypatch


root = Tk()
text = Text(root, width = 12, height = 5, wrap = WORD)
text.insert(END, 'This is an example text.')
text.pack()

def test(event):
    print "displaylines:", text.count("1.0", "end", "displaylines")
    print "lines:", text.count("1.0", "end", "lines")

text.bind('<Map>', test)

root.mainloop()

或Button取代bind

from Tkinter import *

#-------------------------------------------

def count_monkeypatch(self, index1, index2, *args):
    args = [self._w, "count"] + ["-" + arg for arg in args] + [index1, index2]

    result = self.tk.call(*args)
    return result

Text.count = count_monkeypatch

#-------------------------------------------

def test(): # without "event"
    print "displaylines:", text.count("1.0", "end", "displaylines")
    print "lines:", text.count("1.0", "end", "lines")

#-------------------------------------------

root = Tk()
text = Text(root, width = 12, height = 5, wrap = WORD)
text.insert(END, 'This is an example text.')
text.pack()

Button(root, text="Count", command=test).pack()

root.mainloop()

Tkinter - 使用自动换行计算文本小部件中的行

1 个答案: