Question

我有一个像这个例子的对象数组：

[
    {"idroom":"3","idoption":"1","included":"0"},
    {"idroom":"3","idoption":"2","included":"0"},
    {"idroom":"3","idoption":"6","included":"1"},
    {"idroom":"3","idoption":"7","included":"1"},
    {"idroom":"3","idoption":"16","included":"0"},
    {"idroom":"3","idoption":"17","included":"0"}
]

但如果我做了

foreach ($array_of_objects as $single) { 
    ... 
    fwrite( $single->idroom) 
}

我得到一个空文件......为什么？

修改

为了获得那个对象数组，我从javascript开始，如下所示：

var dataAssociates = {};
var associatesRecords = [];
dataAssociates = { "idroom": dataViewRooms.getItem(gridRooms.getSelectedRows()).roomId,
   "idoption": $(this).find('input[name="option_name"]').attr('id'), 
   "included": (
          $(this).find('input[name="enabled_default"]').prop('checked')
              ? '1' : '0')
};
associatesRecords.push(dataAssociates);
...
$.ajax({.... , 'element' : JSON.stringify(associatesRecords) ,... });

Answer 1

$obj = new stdClass();
$obj->idroom = "3";

$obj->idoption = "1";
$obj->included = "0";
$array_of_objects[] = $obj;

$obj->idoption = "2";
$obj->included = "0";
$array_of_objects[] = $obj;

$obj->idoption = "6";
$obj->included = "1";
$array_of_objects[] = $obj;

$obj->idoption = "7";
$obj->included = "1";
$array_of_objects[] = $obj;

$obj->idoption = "16";
$obj->included = "0";
$array_of_objects[] = $obj;

$obj->idoption = "17";
$obj->included = "0";
$array_of_objects[] = $obj;

$filename = 'test.txt';
    $handle = fopen($filename, 'w');
 if (!$handle) {
     echo "Cannot open file ($filename)";
     exit;
}

foreach ($array_of_objects as $single) {
    fwrite($handle, $single->idroom);
}
fclose($handle);

Answer 2

没关系，我现在想出了自己......我只是想做：

$data = json_decode(stripslashes($_REQUEST['element']));
foreach ($data as $single) {
    $sql = "INSERT INTO .... VALUES ( $single->idroom, $single->idoption, $single->included )";
    ...
}

所以它有效！无论如何，感谢大家！

干杯！路易

foreach for PHP中的对象数组

2 个答案: