Question

我使用Retrofit 2库，我需要像这样发送POST JSON请求：

{
   "datetime": 0,
   "body": {
       "gymId": "17C1B14C-C21F-41EE-BF75-F0E7843DB638",
       "customerName": "test",
       "customerEmail": "test@test.ru",
       "content": "test"
   }
}

我如何使用RequestBody发送此请求？

 Call<ApiClubRequest> clubContact(@Body RequestBody requestBody);

或者可以轻易提出这样的要求？

这是我的OkHttp设置的接口类。

public class RestClient {

private static ClassApiInterface WordClassApiInterface ;
private static String baseUrl = "http://my adddress" ;


public static WorldClassApiInterface getClient() {
    if (WordClassApiInterface == null) {
        OkHttpClient okClient = new OkHttpClient();
        okClient.interceptors().add(new Interceptor() {
            @Override
            public Response intercept(Chain chain) throws IOException {
                Response response = chain.proceed(chain.request());
                return response;
            }
        });

        Retrofit client = new Retrofit.Builder()
                .baseUrl(baseUrl)
                .client(okClient)
                .addConverterFactory(GsonConverterFactory.create())
                .build();
        ApiInterface = client.create(ApiInterface.class);

    }
    return ClassApiInterface ;
}

public static  Call<ApiClubRequest> clubcontact(String gymId, String customerName, String
        customerEmail, String content){
    ClubContactRequest request = new ClubContactRequest();
    request.gymId = gymId;
    request.customerName = customerName;
    request.customerEmail = customerEmail;
    request.content = content;
    return ApiInterface.clubContact(request);
}

  @Headers("Content-Type: application/json")
    @POST("/hotline")
    Call<ApiClubRequest> clubContact(@Body ClubContactRequest requestBody);

} }

Answer 1

创建一个请求类并创建与JSON中名称相同的字段：

public class ClubContactRequest {

    public String gymId;
    public String customerName;   
    public String customerEmail;
    public String content;
}

修改POST @Body：

Call<ApiClubRequest> clubContact(@Body ClubContactRequest requestBody);

然后实施请求：

public Call<ApiClubRequest> clubcontact(String gymId, String customerName, String customerEmail, String content){
    ClubContactRequest request = new ClubContactRequest();
    request.gymId = gymId;
    request.customerName = customerName;
    request.customerEmail = customerEmail;
    request.content = content;
    return yourApiInterface.clubContact(request);
}

使用RequestBody改进2 Raw JSON请求

1 个答案: