我想知道是否有办法让一个数组的最小值和最大值得到另一个数组,或类似的东西:
var numbers = ['10','15','20','25','30','35','40','45','50'];
var getnumbers = function(min,max){
//return a result that is push to another array, in this case "results"
};
getnumbers(10,30);
console.log(results);
输出应该给我一些像10 - 15 - 20 - 25 - 30
答案 0 :(得分:2)
略有不同的方法,具有用于过滤的自定义回调函数。
function filterNumbers(min, max) {
return function (a) { return a >= min && a <= max; };
}
var numbers = ['10', '15', '20', '25', '30', '35', '40', '45', '50'],
result = numbers.filter(filterNumbers(10, 30));
document.write('<pre>' + JSON.stringify(result, 0, 4) + '</pre>');
答案 1 :(得分:0)
您可以执行以下操作:numbers.filter(function (value) { return value >= 10 && value <= 30 });
如果您确实希望输出为N1 - N2 - N3 ... - NN
,请执行numbers.filter(function (value) { return value >= 10 && value <= 30 }).join(' - ');
答案 2 :(得分:0)
试试这个
var numbers = ['10','15','20','25','30','35','40','45','50'];
var output = "";
var getnumbers = function(min,max){
for (var i = 0; i < numbers.length; i++){
if(numbers[i] >= min && numbers[i] <= max){
output += numbers[i] + "-";
}
}
};
getnumbers(10,30);
console.log(output);
答案 3 :(得分:0)
JavaScript具有内置功能来解决此问题。
let numbers = ['10','15','20','25','30','35','40','45','50'];
// Get all elements between '10' and '30'
let result = numbers.splice(numbers.indexOf('10'),numbers.indexOf('30') + 1);
console.log(result);
// If you want the answer to literally be '10-15-20-25-30'
let resultString = "";
for(const i in result){
resultString.concat(`${result[i]}-`)
}
console.log(resultString);