getPrincipal()方法返回匿名用户

时间:2015-11-18 09:46:27

标签: java web-services spring-security roles

我正在尝试通过spring安全方法获取连接用户

public static User getConnectedUser() {
    Authentication auth = SecurityContextHolder.getContext().getAuthentication();
    User currentUser=auth.getPrincipal();
}

当我使用postman从webservice get方法调用此方法时,即使登录,它也会返回anonymousUser。 这是我的spring安全配置:

<http auto-config="true" use-expressions="true">
    <intercept-url pattern="/app/admin/**" access="hasRole('ROLE_ADMIN')"/>
    <intercept-url pattern="/app/passwordHint*" access="hasAnyRole('ROLE_USER','ROLE_ADMIN','ROLE_ANONYMOUS')"/>
    <intercept-url pattern="/app/requestRecoveryToken*" access="hasAnyRole('ROLE_USER','ROLE_ADMIN','ROLE_ANONYMOUS')" />
    <intercept-url pattern="/app/updatePassword*" access="hasAnyRole('ROLE_USER','ROLE_ADMIN','ROLE_ANONYMOUS')" />
    <intercept-url pattern="/app/signup*" access="hasAnyRole('ROLE_USER','ROLE_ADMIN','ROLE_ANONYMOUS')"/>
    <intercept-url pattern="/app/**" access="hasAnyRole('ROLE_USER','ROLE_ADMIN')"/>
    <form-login login-page="/login" authentication-failure-url="/login?error=true" login-processing-url="/j_security_check"/>
    <remember-me user-service-ref="userDao" key="e37f4b31-0c45-11dd-bd0b-0800200c9a66"/>
    <custom-filter ref="ajaxTimeoutRedirectFilter" after="EXCEPTION_TRANSLATION_FILTER"/>
</http>

即使我将此行<intercept-url pattern="/*" access="hasAnyRole('ROLE_USER','ROLE_ADMIN')"/>添加到上述配置中,它也会返回anonymousUser。

这是邮递员要求的网址。

http://localhost:8080/myApp/services/api/seal/

1 个答案:

答案 0 :(得分:2)

Yor intercept-url都不匹配,因为您的路径以services而不是app开头。

如果您的上下文根为myApp,则您的配置应为:

<intercept-url pattern="/services/**" access="hasAnyRole('ROLE_USER','ROLE_ADMIN')"/>