Question

我使用实时录入工作objc tableview解析代码。但是节目只匹配1排。我想显示所有匹配的行。我的工作代码在这里。

我工作的远程json文件

{
   "company" : [
        {
         "description" : "example company , Jordan",
         "id" : "90",
         "place_id" : "90"
      } {
         "description" : "example company 2 , Qatar",
         "id" : "362578",
         "place_id" : "362578"
      } {
         "description" : "example company 3 , Spain",
         "id" : "432589",
         "place_id" : "432589"
      },    
    {
         "description" : " ",
         "id" : "1",      
         "place_id" : "1"
      }
   ],
   "status" : "OK"
}

这里的Objc代码

#import "ViewController.h"
#import "Common/Constants.h"
#import "Place.h"

@interface ViewController (){
    NSMutableArray *response;
    Place *place;
    NSMutableArray *places;
}
@end


NSString *links;

@implementation ViewController
@synthesize toggleSwitch;

- (void)viewDidLoad {
    [super viewDidLoad];
    // Do any additional setup after loading the view, typically from a nib.
//    [self.txtSearchField becomeFirstResponder];
    self.tableViewSearchResult.hidden = YES;

     self.toggleSwitch.on = true;


        self.switchLabel.text = @"Coms";

        NSString *valueToSave = @"http://bla.com/company.php?";
        [[NSUserDefaults standardUserDefaults] setObject:valueToSave forKey:@"preferenceName"];
        [[NSUserDefaults standardUserDefaults] synchronize];


}




- (IBAction)backChange:(id)sender {
    if ([sender isOn] == YES) {
        _switchLabel.text = @"Firmalar";



        NSString *valueToSave = @"http://bla.com/company.php?";
        [[NSUserDefaults standardUserDefaults] setObject:valueToSave forKey:@"preferenceName"];
        [[NSUserDefaults standardUserDefaults] synchronize];


        NSLog(@"");


    } else {


        NSString *valueToSave = @"http://bla.com/company2.php?";
        [[NSUserDefaults standardUserDefaults] setObject:valueToSave forKey:@"preferenceName"];
        [[NSUserDefaults standardUserDefaults] synchronize];


  _switchLabel.text = @"Ülkeler";


        NSLog(@"");


          }






}





#pragma mark - 
-(void)searchForResult:(NSString *)input{


    NSString *savedValue = [[NSUserDefaults standardUserDefaults]
                            stringForKey:@"preferenceName"];


     NSString *urlString = [NSString stringWithFormat:@"%@gelen=%@",savedValue,input];

      NSLog(@"link = %@",urlString);

    NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:urlString]];


}

#pragma mark - UITextField Delgate
-(BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{

    if (![string isEqualToString:@""] && [string length]>0) {
        NSString *keyword = [textField.text stringByAppendingString:string];
        NSLog(@"String : %@",keyword);
        if ([keyword length]>=4) {
            [self searchForResult:keyword];
        }
    }
    return YES;
}
#pragma mark - UITableViewDelegate 

-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath{
    place = [places objectAtIndex:indexPath.row];
    self.txtSearchField.text = place.placeName;
    NSLog(@"Selected placeID : %@",place.placeID);
    self.tableViewSearchResult.hidden = YES;
}

#pragma mark - UITableViewDataSource

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath{
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"cell"];

    if (nil == cell) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault
                                      reuseIdentifier:@"cell"];
    }
    place = [places objectAtIndex:indexPath.row];
    NSLog(@"Place ID : %@, Place Name : %@",place.placeID,place.placeName);
    cell.textLabel.text = [place placeName];
    return cell;
}
-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section{
    return [places count];
}

- (void)didReceiveMemoryWarning {
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}

@end

匹配时，另外1个给我这个错误（如果匹配1成功显示）

Connection Error : (null)

我工作了大约7-8个小时，但我没有解决它:)我需要你的帮助谢谢你的一切。我认为这很容易解决，但我仍然无法解决。

Answer 1

你的json字符串应该是这样的

{
   "company" : [
        {
         "description" : "example company , Jordan",
         "id" : "90",
         "place_id" : "90"
      }, {
         "description" : "example company 2 , Qatar",
         "id" : "362578",
         "place_id" : "362578"
      }, {
         "description" : "example company 3 , Spain",
         "id" : "432589",
         "place_id" : "432589"
      },    
    {
         "description" : " ",
         "id" : "1",      
         "place_id" : "1"
      }
   ],
   "status" : "OK"
}

满足您的代码并获得超过1个rec。

根据RFC 4627（JSON规范），它是一个有效的josn。因此你有1个回应。

Objc live Json Parsing Only只显示1项错误

1 个答案: