Question

这是我的代码，其中我使用了readCookies函数，但是当它没有响应时，它在div中没有显示任何内容，即使警报也无效。

seconds = readCookie('countdown') || 60;
alert(seconds);

function secondPassed() {
    seconds--;
    var minutes = parseInt(seconds / 60);
    var remainingSeconds = parseInt(seconds % 60);
    if (remainingSeconds < 10) {
        remainingSeconds = "0" + parseInt(remainingSeconds);
    }
    document.getElementById('countdown').innerHTML = minutes + " mins : " + remainingSeconds + " secs";
    if (parseInt(seconds) === 0) {
        alert("Time is over");
        clearInterval(countdownTimer);
        document.getElementById('countdown').innerHTML = "Time is Over";
        document.forms["myForm"].submit();
        document.location.href = "examresult.jsp";
    }
}
var countdownTimer = setInterval(function () {
    secondPassed();
    if (seconds === 0) {
        eraseCookie(seconds);
    } else {
        createCookie(seconds, seconds, 7);
    }
}, 1000);

Answer 1

在页面卸载之前将值存储在cookie或浏览器存储中，并在页面刷新时从cookie或浏览器存储中重新加载。

例如（伪代码）：

window.onunload = function(){
     set_cookie('timer', timer) /* you need to implement this function */;
}

window.onload = function() {
   timer = get_cookie('timer'); /* you need to implement this function */
   if ( null == timer ) timer = 0; /* not page refresh, start a new timer */
}

如何避免使用java脚本重置页面刷新/页面加载上的计时器值？

1 个答案: