我正在使用表单来获取用户名和密码的输入以将值存储到数据库中,一旦提交表单我已经定义了一个表来显示来自users表的所有值,它有3个字段(id ,name,pass)我想用它的id删除每条记录。
我使用以下代码从users表中获取数据:
while($row = mysql_fetch_assoc($result_select)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['pass'] . "</td>";
echo "</tr>"; }
我想添加删除超链接以按ID删除特定记录。
我尝试使用以下代码,但我无法实现它。
if(mysql_num_rows($result_select) > 0) {
if(isset($_POST['id'])) {
$query_delete = "DELETE FROM users WHERE id =" .$_POST['id'];
$result_delete = mysql_query($query_delete);
}
echo "<table cellpadding=10 border=1>";
while($row = mysql_fetch_assoc($result_select)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['pass'] . "</td>";
echo "<td><a href=".$_SERVER['PHP_SELF']."?id=".$row[id].">Delete</a></td>";
echo "</tr>";
}
echo "</table>";
}
我是编程的新手,如果有人用简单的话语解释我,我将不胜感激..谢谢:)
答案 0 :(得分:1)
首先将您的删除代码放在您的页面中,如下所示:
if(isset($_POST['submit'])) {
for($i = 0; $i < count($_POST['del']); $i++)
{
// check which records to delete
if (isset($_POST['del'][$i]))
{
$query_delete = "DELETE FROM users WHERE id = " . (int) $_POST['del'][$i];
$result_delete = mysql_query($query_delete) or die(mysql_error());
}
}
echo 'Record Deleted !!' . '<br /><br />';
}
稍后输入您的选择代码并按如下方式修改:
echo '<form action="" method="POST">';
while($row = mysql_fetch_assoc($result_select)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['pass'] . "</td>";
echo "<td><input type=\"checkbox\" name=\"del[]\"></td>";
echo "</tr>";
}
echo '<input type="submit" name="submit">';
echo '</form>';
答案 1 :(得分:0)
您需要将$_POST
更改为$_GET
,这样才有效。
if(isset($_GET['id'])) {
$query_delete = "DELETE FROM users WHERE id =" .$_GET['id'];
$result_delete = mysql_query($query_delete);
并且还将属性值放在双引号内,如此
echo '<td><a href="'.$_SERVER['PHP_SELF'].'?id='.$row[id].'">Delete</a></td>';