Question

对于第一位，当我打印出＆＃34; ask2＆＃34;时，它打印出＆＃34;退出＆＃34;而不是它应该打印的车牌。

     ask = input("-Would you like to 1 input an existing number plate\n--or 2 view a random number\n1 or 2: ")
        ask2 = ""
        plate = ""
        if int(ask) == 1:
            ask2 = ""
            print("========================================================================")
            while ask2 != 'exit':
                ask2 = input ("Please enter it in such form (XX00XXX): ").lower()
                # I had no idea that re existed, so I had to look it up.
                # As your if-statement with re gave an error, I used this similar method for checking the format.
                # I cannot tell you why yours didn't work, sorry.
                valid = re.compile("[a-z][a-z]\d\d[a-z][a-z][a-z]\Z")
                                   #b will start and end the program, meaning no more than 3-4 letters will be used.
                # The code which tells the user to enter the right format (keeps looping)
                # User can exit the loop by typing 'exit'
                while (not valid.match(ask2)) and (ask2 != 'exit'):
                    print("========================================================================")
                    print("You can exit the validation by typing 'exit'.")
                    time.sleep(0.5)
                    print("========================================================================")
                    ask2 = input("Or stick to the rules, and enter it in such form (XX00XXX): ").lower()
                if valid.match(ask2):
                    print("========================================================================\nVerification Success!")
                    ask2 = 'exit'  # People generally try to avoid 'break' when possible, so I did it this way (same effect)

**print("The program, will determine whether or not the car "+str(plate),str(ask)+" is travelling more than the speed limit")**

此外，我正在寻找一些好的附加代码（将数据放入列表中）和打印。这就是我所做的;

  while tryagain not in ["y","n","Y","N"]:
        tryagain = input("Please enter y or n")
    if tryagain.lower() == ["y","Y"]:
        do_the_quiz()
    if tryagain==["n","N"]:
        cars.append(plate+": "+str(x))

print(cars)

Answer 1

当您打印ask2时，它会打印并退出＆＃39;因为您将其设置为使用ask2 = 'exit'退出，并且在ask2设置为＆＃39;退出＆＃39;之前您的循环无法终止。

您可以将ask2用于用户的输入，使用另一个变量loop来确定何时退出循环。例如：

loop = True
while loop:
    # ...
    if valid.match(ask2) or ask2 == 'exit':
        loop = False

我不太确定你的其他代码块试图实现什么，但是你测试tryagain的方式不正确，它永远不会等于两个元素列表，例如["y","Y"] ，也许你打算使用in ?,这个改变显示了至少解决这个问题的一种方法：

while tryagain not in ["y","n","Y","N"]:
    tryagain = input("Please enter y or n")
if tryagain.lower() == "y":
    do_the_quiz()
else:
    cars.append(plate+": "+str(x))

print(cars)

代码不打印我寻求的东西

1 个答案: