我正在尝试获取sql中每个日期时间字段的最新数据。任何人都可以帮我解决这个问题.. 这是我的表结构。
| ID | USER | TIME |
-------------------------------------
| 2 | abc | 2009-01-01 01:00:00 |
| 3 | abc | 2009-01-01 22:00:00 |
| 5 | abc | 2009-01-01 10:00:00 |
| 6 | xyz | 2009-01-02 01:00:00 |
| 7 | xyz | 2009-01-02 22:00:00 |
| 8 | xyz | 2009-01-02 10:00:00 |
我希望输出像这样。
| ID | USER | TIME |
-------------------------------------
| 3 | abc | 2009-01-01 22:00:00 |
| 7 | xyz | 2009-01-02 22:00:00 |
编辑:需求变更。正如我所说,我希望每个用户都能获得每个日期的最新记录。
| ID | USER | TIME |
-------------------------------------
| 2 | abc | 2009-01-01 01:00:00 |
| 3 | abc | 2009-01-01 22:00:00 |
| 5 | abc | 2009-01-01 10:00:00 |
| 6 | xyz | 2009-01-01 01:00:00 |
| 7 | xyz | 2009-01-01 22:00:00 |
| 8 | xyz | 2009-01-01 10:00:00 |
| 10 | abc | 2009-01-04 09:00:00 |
| 11 | abc | 2009-01-04 02:00:00 |
| 15 | xyz | 2009-01-04 04:00:00 |
| 25 | xyz | 2009-01-04 06:00:00 |
我希望输出像这样。
| ID | USER | TIME |
-------------------------------------
| 3 | abc | 2009-01-01 22:00:00 |
| 7 | xyz | 2009-01-01 22:00:00 |
| 10 | abc | 2009-01-04 09:00:00 |
| 25 | xyz | 2009-01-04 06:00:00 |
答案 0 :(得分:0)
答案 1 :(得分:-1)
试试这个:
SELECT ID,USER,TIME FROM tbl_name Group By User Order By TIME DESC,USER ASC;