Question

我一直试图弄清楚如何在LineChart已经制作之后从LineChart中删除它。我试过用我想要的系列重新创建场景，但那不起作用。我做了一些故障排除，发现该系列实际上已更改并减少为null，但即使系列为空，该行仍然存在。然后，一旦将系列更改为新数字，它会尝试将点连接到不应存在的旧点。如果有人能帮助我，我将非常感激。

public class GraphSection {
NumberAxis xAxis;
NumberAxis yAxis;
LineChart<Number, Number> lineChart;
Scene scene;
XYChart.Series series1, series2, series3, series4;




public GraphSection(){
    xAxis = new NumberAxis();
    yAxis = new NumberAxis();
    lineChart = new LineChart<Number,Number>(xAxis,yAxis);
    lineChart.setTitle("Test Graph");
    lineChart.setCreateSymbols(false);
    lineChart.setLegendVisible(false);

    series1 = new XYChart.Series();
    series2 = new XYChart.Series();
    series3 = new XYChart.Series();
    series4 = new XYChart.Series();

    lineChart.getData().addAll(series1, series2, series3, series4);
    scene = new Scene(lineChart,400,300);


}
public Scene getGraph(){
    return this.scene;

}
public void addPoints(int n){

    if(n == 1){
        //Test Points
        series1.getData().add(new XYChart.Data(1,50));
        series1.getData().add(new XYChart.Data(2,60));
        series1.getData().add(new XYChart.Data(3,70));
        series1.getData().add(new XYChart.Data(4,80));
        series1.getData().add(new XYChart.Data(5,90));

    }
    else if(n == 2){
        //More Test Points
        series1.getData().add(new XYChart.Data(1,70));
        series1.getData().add(new XYChart.Data(2,80));
        series1.getData().add(new XYChart.Data(3,90));
        series1.getData().add(new XYChart.Data(4,100));
        series1.getData().add(new XYChart.Data(5,110));
    }
    else if(n == 3){

    }
    else if(n == 4){

    }

}

public void removePoints(int n){
    Series s;
    LineChart l = this.lineChart;
    if(n == 1){
        s = this.series1;
        s.getData().clear();
        l.removeSeriesFromDisplay(s);  //This is the method I would guess I need but 
                                       //it is "not visible" and thus produces
                                       // an error when I try to compile.
    }
    else if(n==2){
        series2 = this.series2;
    }
    else if(n==3){
        series3 = this.series3;
    }
    else if(n==4){
        series4 = this.series4;
    }


}

}

编辑：因此虽然.remove()将使其从图中删除该行，但它也会抛出IllegalStateException。虽然这很丑，但不会导致程序崩溃，然而，当我将数据点添加回系列时，它将不会绘制新点的图形。因此，一个潜在的解决方案是动态地将一系列添加到LineChart中。如果有人知道如何做到这一点，那可能会解决我的问题。

编辑：我改变了.addPoints（2）;添加点到系列1，我包括下面的图片（删除后添加（）只给出一个空白图表。）我还包括我从中调用该类的代码。

    //Bottom
    JFXPanel bottom = new JFXPanel();
    final GraphSection gs = new GraphSection();
    bottom.setScene(gs.getGraph());
    gs.addPoints(1);

    //ActionListeners
    testButton1.addActionListener(new ActionListener(){
        public void actionPerformed(ActionEvent e){
            gs.removePoints(1);
            System.out.println(gs.series1.getData()); //Used for debugging
        }
    });

    testButton2.addActionListener(new ActionListener(){
        public void actionPerformed(ActionEvent e){
            gs.addPoints(2);
            System.out.println(gs.series1.getData());
        }
    });

Start with .addPoints(1); This is what happens with just .getData().clear();

Answer 1

是的，问题实际上是在Swing JFrame中尝试使用JFXPanel。这意味着出现了illegalStateException。通过更改在JavaFX阶段运行的代码，这允许remove（）工作，然后您可以使用lineChart.getData（）。add（Series）;轻松地动态添加新系列。您可以将swing组件与SwingNodes合并，但我的建议是将GUI重新编码为所有JavaFX。

如何从LineChart中删除行？

1 个答案: