Question

我的输入文件为：

1 sentences, 6 words, 1 OOVs
1 zeroprobs, logprob= -21.0085 ppl= 15911.4 ppl1= 178704
6 words, rank1= 0 rank5= 0 rank10= 0
7 words+sents, rank1wSent= 0 rank5wSent= 0 rank10wSent= 0 qloss= 0.925606 absloss= 0.856944

file input.txt : 1 sentences, 6 words, 1 OOVs
1 zeroprobs, logprob= -21.0085 ppl= 15911.4 ppl1= 178704
6 words, rank1= 0 rank5= 0 rank10= 0
7 words+sents, rank1wSent= 0 rank5wSent= 0 rank10wSent= 0 qloss= 0.925606 absloss= 0.856944

我想提取单词ppl及其后面的值，在这种情况下：ppl = 15911.4

我正在使用此代码：

with open("input.txt") as openfile:
    for line in openfile:
       for part in line.split():
          if "ppl=" in part:
              print part

然而，这只是提取单词ppl而不是值。我还想打印文件名。

预期产出：

input.txt, ppl=15911.4

我该如何解决这个问题？

Answer 1

您可以使用enumerate功能，

list2

示例：

with open("input.txt") as openfile:
    for line in openfile:
       s = line.split()
       for i,j in enumerate(s):
          if j == "ppl=":
              print s[i],s[i+1]

仅打印第一个值

>>> fil = '''1 zeroprobs, logprob= -21.0085 ppl= 15911.4 ppl1= 178704
6 words, rank1= 0 rank5= 0 rank10= 0'''.splitlines()
>>> for line in fil:
        s = line.split()
        for i,j in enumerate(s):
            if j == "ppl=":
                print s[i],s[i+1]


ppl= 15911.4
>>>

Answer 2

您可以使用简单的计数器修复它：

found = False
with open("input.txt") as openfile:
     for line in openfile:
         if not found:
             counter = 0
             for part in line.split():
                  counter = counter + 1
                  if "ppl=" in part:
                      print part
                      print line.split()[counter]
                      found = True

Answer 3

您可以将从line.split()生成的列表分配给变量，然后使用while循环，使用i作为计数器进行迭代，当您点击'ppl ='时，您可以返回'ppl ='和下一个索引

with open("input.txt") as openfile:
for line in openfile:
    phrases = line.split()
    i = 0
    while i < len(phrases):
        if 'ppl=' in phrases[i]
            print "ppl= " + str(phrases[i + 1])
        i += 1

从文本文件

3 个答案: