Question

我有下表：

 ID    Key   Value
 1     From  x
 1     To    Y
 1     CC    a
 2     From  Z
 2     To    X
 2     CC    b
 3     From  X
 3     To    Y  
 3     CC    c
 4     From  X
 4     To    Z
 4     CC    d

我想要Id 1和3作为结果，其中key =“From”和value =“x”，其中key =“To”和value =“Y”（From-＆gt; To应该是x-＆gt; Y）它应该是这样的

SELECT Id
FROM table_name
WHERE REGEXP_LIKE(KEY, '(^|\s)from(\s|$)', 'i')
    AND REGEXP_LIKE(value, '(^|\s)x(\s|$)', 'i')
    AND
WHERE
WHERE REGEXP_LIKE(KEY, '(^|\s)to(\s|$)', 'i')
    AND REGEXP_LIKE(value, '(^|\s)y(\s|$)', 'i')

有可能解决这个问题吗？

Answer 1

使用条件SUM

SqlFiddleDemo

SELECT ID
FROM Table1
GROUP BY ID
HAVING 
      SUM(CASE WHEN "Key" = 'From' and LOWER("Value") = 'x' THEN 1 ELSE 0 END) = 1 
 AND  SUM(CASE WHEN "Key" = 'To' and LOWER("Value") = 'y' THEN 1 ELSE 0 END) = 1

<强>输出

| ID |
|----|
|  1 |
|  3 |

Answer 2

将表格连接到自身并进行相应过滤。

    SELECT ID
    FROM 
            Table t1
            INNER JOIN Table t2
            ON t1.ID = t2.ID
    WHERE
            t1.Key = 'From' AND
            t1.Value = 'x' AND
            t2.Key = 'To' AND
            t2.Value = 'y'

多个where子句

2 个答案: