我正在尝试学习Spring 4 MVC for Restful Web服务的基础知识,但这不是问题所在。
在我的@RestController中,我想使用Spring的Unmarshaller接口,并且特别使用Jaxb2Marshaller。所以,现在,我有......
@RestController
@RequestMapping("/postuser")
public class MyController {
private String xsdFileName = "User.xsd";
private Jaxb2Marshaller unmarshaller;
public MyController() {
unmarshaller = new Jaxb2Marshaller();
unmarshaller.setPackagesToScan("com.mypackage");
}
// rest of class
}
哪个有效。但是我如何通过@Autowired来设置unmarshaller,或者通过XML配置文件使用Spring的依赖注入呢?
我的dispatcher-servlet.xml文件很简单......
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd">
<context:component-scan base-package="com.mypackage" />
<mvc:annotation-driven />
</beans>
非常感谢您的帮助和帮助建议。
克里斯
答案 0 :(得分:1)
您可以使用配置类
@Configuration
public MyClass{
@Bean
public Jaxb2Marshaller unmarshaller() {
Jaxb2Marshaller unmarshaller = new Jaxb2Marshaller();
unmarshaller.setPackagesToScan("com.mypackage");
return unmarshaller;
}
}
然后在您的控制器中
@RestController
@RequestMapping("/postuser")
public class MyController {
private String xsdFileName = "User.xsd";
@Autowired
private Jaxb2Marshaller unmarshaller;
// rest of class
}
bean定义你也可以在xml文件中使用
<bean id="unmarshaller" class="package.Jaxb2Marshaller">
<property name="packagesToScan">
<value>com.mypackage</value>
</property>
</bean>