Question

我输入了一个UNICODE字符串，我想把它转换为\ uxxxx格式但如果我写这段代码

class Master(numOfWorkers: Int, numOfMessages: Int, numOfElements: Int,  listener: ActorRef) extends Actor {
  var pi: Double = _
  var numOfResults: Int = _
  val start: Long = System.currentTimeMillis

  val workerRouter = {
    val routees = Vector.fill(5) {
      val r = context.actorOf(Props[Worker])
      context watch r
      ActorRefRoutee(r)
    }
    Router(RoundRobinRoutingLogic(), routees)
  }

    def receive = {
        case Calculate => for (i <- 0 until numOfMessages) workerRouter.route(Work(i * numOfElements, numOfElements), sender())
        case Result(value) =>
          pi += value
          numOfResults += 1
          if (numOfResults == numOfMessages) {
            listener ! PiApproximation(pi, duration = (System.currentTimeMillis - start).millis)
            context.stop(self)
    }
  }
}

我有这个结果：

    String inString = "èaéKlüfsäöråédéroße";
    for (int i = 0; i < inString.length(); i++) {
        Integer charCode = (int)inString.charAt(i);
        result += "\\u" + strlenFix(charCode.toString().toUpperCase());
    }
    static public String strlenFix(String str) {
    while (str.length()<4) str="0"+str;
    return str;
}

Answer 1

试试这个

    public static void main(String[] args) {
    String result = "";

     String inString = "èaéKlüfsäöråédéroße";
        for (int i = 0; i < inString.length(); i++) {
            Integer charCode = (int)inString.charAt(i);
            result += "\\u" + Integer.toHexString(charCode) ;
        }
    System.out.println(result);
}

 static public String strlenFix(String str) {
        while (str.length()<4) str="0"+str;
        return str;
    {

Answer 2

再次在引用上调用静态方法！

正因为如此，您认为charCode.toString(16)会在 toString上调用charCode 并返回其16个基本版本，但会将其编译为{{1} }。

你可能想要像Integer.toString(16)这样的东西。

Answer 3

所以，就这样做：

public static String unicodeEscaped(char ch) {
  if (ch < 0x10) {
      return "\\u000" + Integer.toHexString(ch);
  } else if (ch < 0x100) {
      return "\\u00" + Integer.toHexString(ch);
  } else if (ch < 0x1000) {
      return "\\u0" + Integer.toHexString(ch);
  }
  return "\\u" + Integer.toHexString(ch);
}
String inString = "èaéKlüfsäöråédéroße";
for (int i = 0; i < inString.length(); i++) {
    Integer charCode = (int)inString.charAt(i);
    result += unicodeEscaped(charCode);
}

Answer 4

查看以下代码段

public static void main(String[] args) {

String result = "";
 String inString = "èaéKlüfsäöråédéroße";
            for (int i = 0; i < inString.length(); i++) {
    result += "\\u" + Integer.toHexString(inString.charAt(i) | 0x10000)+" ";
    }
    System.out.println(result);
}

Answer 5

那些\uXXXX转义符通常后跟一个4位十六进制号。

将代码点转换为此类Unicode转义的最简单方法是使用String.format：

String escaped = String.format("\\u%04X", (int) codePoint);

你可以放弃你的strlenFix功能，所以你的循环就是：

for (int i = 0; i < inString.length(); i++) {
    result += String.format("\\u%04x", (int) inString.charAt(i));
}

如何在java中转换外来字符？

5 个答案: