我正在尝试从名为input的txt文件中读取三个变量 input.txt包含12 33.44和Peter 当我运行程序时,这些变量不会输出
package lab9;
import java.util.Scanner; // Needed to use Scanner for input
import java.io.File; // Needed to use File
import java.io.FileNotFoundException; // Needed for file operation
public class FileScanner
{
public static void main(String[] args)
// Needed for file operation
throws FileNotFoundException
{
// Declare the int variable
int a=0;
//Declare the floating point number
double b=0;
//Declare the string variable
String s=null;
//Declare a variable to hold the sum
double sum =0;
// Create a file object that takes "input.txt" as input
File oInput= new File("input.txt") ;
// Setup a Scanner to read from the text file that you created
Scanner gilz=new Scanner(oInput);
// use nextInt() to read the integer
while (gilz.hasNextInt())
{
a = gilz.nextInt();
}
System.out.println ("the integer read is " + a);
// use nextDouble() to read double
while(gilz.hasNextDouble())
{
b = gilz.nextDouble();
}
System.out.println ("the floating point number read is "+ b);
// use next() to read String
while(gilz.hasNextLine())
{
s = gilz.nextLine();
}
System.out.println ("the string read is "+ s);
while((gilz.hasNextDouble())&&(gilz.hasNextInt()))
{
sum = a + b;
}
System.out.println("HI! "+s +", the sum of "+a+"and "+b+" is "+sum);
}
}
当我尝试运行程序时,我没有输出,屏幕上没有打印变量 如何使用.nextInt()或.next()方法让我的扫描仪从txt文件中读取?
答案 0 :(得分:-2)
使用您将阅读的文件的完整路径。
我正在使用FileReader和BufferedReader的示例,您需要使用新的File("c:\\input.txt)
执行相同的操作。
请看下面的示例:
public static void main(String[] args) {
BufferedReader br = null;
try {
String sCurrentLine;
br = new BufferedReader(new FileReader("C:\\input.txt"));
while ((sCurrentLine = br.readLine()) != null) {
System.out.println(sCurrentLine);
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (br != null)br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}