Question

我正在使用XSLT解析文档。在XSLT中，我使用document（）函数加载参考文档，我可以访问这两个文档中的项目。源文档和参考文档都有一个名为name的属性。我如何比较一个。我通过声明一个变量来解决这个问题，但是如果可能的话我宁愿这样做。在我看来，我需要将命名空间置于事物之外，但不知道该怎么做。

源文件：

<?xml version="1.0" encoding="UTF-8"?>
<SoccerMatch revision="21" id="2849180" date="20080405" scheduledStart="1245" venue="Emirates Stadium" status="Result" comment="" league="Friendly Match" attendance="60111">
    <stuffhere>stuff</stuffhere>
    <stuffhere>stuff</stuffhere>
    <stuffhere>stuff</stuffhere>
    <stuffhere>stuff</stuffhere>
    <stuffhere>stuff</stuffhere>
</SoccerMatch>

参考文件（comp.xml）：

<?xml version="1.0" encoding="utf-8"?>
<competitions>
    <competition id="100" league="Barclays Premier League"/>
    <competition id="101" league="The Coca-Cola Football League Championship"/>
    <competition id="101" league="The Coca-Cola Football League Championship Play-Offs Semi-Final"/>
    <competition id="101" league="The Coca-Cola Football League Championship Play-Offs Final"/>
    <competition id="102" league="Coca-Cola Football League One"/>
    <competition id="102" league="Coca-Cola Football League One Play-Offs Semi-Final"/>
    <competition id="102" league="Coca-Cola Football League One Play-Offs Final"/>
    <competition id="103" league="Coca-Cola Football League Two"/>
    <competition id="103" league="Coca-Cola Football League Two Play-Offs Semi-Final"/>
    <competition id="103" league="Coca-Cola Football League Two Play-Offs Final"/>
    <competition id="104" league="Blue Square Premier"/>
    <competition id="104" league="Blue Square Premier Play-Offs Semi-Final"/>
    <competition id="104" league="Blue Square Premier Final"/>
    <competition id="105" league="Nationwide Championship Shield"/>
    <competition id="120" league="Clydesdale Bank Premier League"/>
    <competition id="121" league="The Irn-Bru Scottish Football League Championship First Division"/>
    <competition id="121" league="The Irn-Bru Scottish Football League Championship First Division Play-Offs Semi-Final"/>
    <competition id="121" league="The Irn-Bru Scottish Football League Championship First Division Play-Offs Final"/>
    <competition id="122" league="The Irn-Bru Scottish Football League Championship Second Division"/>
    <competition id="122" league="The Irn-Bru Scottish Football League Championship Second Division Play-Offs Semi-Final"/>
    <competition id="122" league="The Irn-Bru Scottish Football League Championship Second Division Play-Offs Final"/>
    <competition id="123" league="The Irn-Bru Scottish Football League Championship Third Division"/>
</competitions>

XSLT

<xsl:template match="/SoccerMatch">
<xmlfeed>
<payload payload_class="mobile_football_match_details" payload_name="Payload">
<xsl:variable name="compId" select="document('comp.xml')/competitions/competition[@league=@league]/@id" />

Answer 1

在xml中看不到“name”属性。你是说“id”吗？我不认为你可以在这里控制命名空间。请参阅Ken Holman关于这一点的讨论here。

我会考虑你对变量的看法。类似的东西：

<xsl:template match="/SoccerMatch">
 <xsl:variable name="matchId" select="@id"/>    
 <xsl:for-each select="document('competitions.xml')/competitions/competition">
   <xsl:if test="$matchId = @id">
     <xmlfeed>
      <payload payload_class="mobile_football_match_details" payload_name="Payload">
        <!-- add more stuff here-->
      </payload>
     </xmlfeed>
   </xsl:if>
 </xsl:for-each>

访问多个源的相同名称元素

1 个答案: