以下是我尝试使用的有效且更新的XML:
<DataSet xmlns="http://tempuri.org/">
<xs:schema xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" id="NewDataSet">
<xs:element name="response">
<xs:complexType>
<xs:sequence>
<xs:element name="user" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:attribute name="id" type="xs:string"/>
</xs:complexType>
</xs:element>
<xs:element name="status" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:attribute name="code" type="xs:string"/>
<xs:attribute name="value" type="xs:string"/>
<xs:attribute name="description" type="xs:string"/>
</xs:complexType>
</xs:element>
<xs:element name="error" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:attribute name="code" type="xs:string"/>
<xs:attribute name="message" type="xs:string"/>
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="operation" type="xs:string"/>
<xs:attribute name="timestamp" type="xs:string"/>
</xs:complexType>
</xs:element>
<xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
<xs:complexType>
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element ref="response"/>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
<diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
<NewDataSet xmlns="">
<response diffgr:id="response1" msdata:rowOrder="0" diffgr:hasChanges="inserted" operation="AUTHENTICATION" timestamp="2015-11-19 18:21:17.457" msdata:hiddenresponse_Id="0">
<user diffgr:id="user1" msdata:rowOrder="0" diffgr:hasChanges="inserted" id="blumaesnetwork" msdata:hiddenresponse_Id="0"/>
<status diffgr:id="status1" msdata:rowOrder="0" diffgr:hasChanges="inserted" code="315" value="FAILED" description="Authentication Failed. User ID Not Found" msdata:hiddenresponse_Id="0"/>
<error diffgr:id="error1" msdata:rowOrder="0" diffgr:hasChanges="inserted" code="-1" message="User Not Found" msdata:hiddenresponse_Id="0"/>
</response>
</NewDataSet>
</diffgr:diffgram>
</DataSet>
使用下面的C#代码:
x.LoadXml(_xmlString);
XDocument x1 = new XDocument();
x1 = XDocument.Parse(_xmlString);
IEnumerable<responseStatus> ListRsts = (from e in x1.Descendants("responseStatus")
select new responseStatus
{
code = e.Element("code").Value,
value = e.Element("value").Value,
description = e.Element("description").Value
});
foreach (var br in ListRsts)
codeField = (br.code);
它不断抛出我错过的错误&#34; diffgr&#34;。
答案 0 :(得分:0)
您作为respsone XML获得的内容是已保存的DataSet。不要试图破译它生成的diffgram,而是更好地利用该类型的ReadXml方法。它完全可以读取xml并在表和Relationships上为您指定行为。
&
在上面的代码中,我读取了表响应中的行,然后获取表状态的子节点。对于每个状态行,使用您似乎感兴趣的三个字段创建匿名类型。您可以通过迭代该匿名类型的IEnumerable来处理它们。