Question

我正在编写一个ASP.NET应用程序，在按钮上单击执行这些操作

使用GUID
将exe文件和Excel模板复制到唯一目录
从网页输入中写一个txt文件
运行exe文件
exe生成输出txt文件
将输出数据放入网页上的asp表
将输出数据从txt文件写入excel模板

点击第二个按钮

下载包含数据的唯一Excel文件

现在所涉及的所有路径都是变量。我想要做的是点击第二个按钮，它允许您下载填充数据的唯一excel文件。无论我尝试什么，我都无法在第二个按钮单击中使用excel文件的唯一路径。

那么如何在第二个按钮单击中传递第一个按钮单击中定义的变量。在第一次单击按钮时创建唯一目录很重要。

以下是一些代码。有很多，所以我只想发布重要的东西

public void Button1_Click(object sender, EventArgs e)
{

    UniqueDirectory d = new UniqueDirectory();
    string dirPath = Request.MapPath("~/App_Data/");             // point to the directory of wispp on the server
    string wisppExe = Server.MapPath("~/App_Data/WisppNew.exe"); // point to the location of wispp on the server
    string fortranLib = Server.MapPath("~/App_Data/libf60rts.dll"); // point to the location of the fortran libray file on the server
    string excelTemplate = Server.MapPath("~/App_Data/WISPP_Template.xls");
    do

    {
        Guid guid = Guid.NewGuid();
        string uniqueSubFolderName = guid.ToString();
        string uniquePath = dirPath + uniqueSubFolderName;

    }
    while (Directory.Exists(d.uniquePath));
    Directory.CreateDirectory(d.uniquePath);

    //copy files to new unique directory
    string wisppUnique = Path.Combine(d.uniquePath, "WisppNew.exe");
    string fortranUnique = Path.Combine(d.uniquePath, "libf60rts.dll");
    string wisppGraphUnique = Path.Combine(d.uniquePath, "WISPPGRA");
    string excelUnique = Path.Combine(d.uniquePath, "WISPP_Template.xls");
    string excelOutput = Path.Combine(d.uniquePath, "WISPP_Output.xls");
    File.Copy(wisppExe, wisppUnique, true);
    File.Copy(fortranLib, fortranUnique, true);
    File.Copy(excelTemplate, excelUnique, true);

    //write data into excel        
    FileStream outputFile = new FileStream(excelOutput, FileMode.OpenOrCreate, FileAccess.Write);
    xssfworkbook.Write(outputFile);
    outputFile.Close();
}

public void Button2_Click(object sender, EventArgs e)
{

    //here I want to use variable excelOutput
    FileInfo file = new FileInfo(excelOutput);

    if(file.Exists)
    {
        Response.Clear();
        Response.ClearHeaders();
        Response.ClearContent();
        Response.AddHeader("Content-Disposition", "attachment; filename=" + file.Name);
        Response.AddHeader("Content-Length", file.Length.ToString());
        Response.ContentType = "Application/x-msexcel";
        Response.Flush();
        Response.TransmitFile(file.FullName);
        Response.End();
    }
}

希望这是有道理的。我已经尝试在第一个按钮单击中放置代码的响应部分，但这使得数据表由于某种原因不可见。此外，我希望用户可以选择下载excel文件，因此我理想情况下需要再次点击按钮。

Answer 1

你的方法不正确，因为按钮可以按任意顺序点击，但如果你要走这条路，你可以做这样的事情。

//hide second button
yourButton2.Visible = false;

public void Button1_Click(object sender, EventArgs e)
{

    UniqueDirectory d = new UniqueDirectory();
    string dirPath = Request.MapPath("~/App_Data/");             // point to the directory of wispp on the server
    string wisppExe = Server.MapPath("~/App_Data/WisppNew.exe"); // point to the location of wispp on the server
    string fortranLib = Server.MapPath("~/App_Data/libf60rts.dll"); // point to the location of the fortran libray file on the server
    string excelTemplate = Server.MapPath("~/App_Data/WISPP_Template.xls");
    do

    {
        Guid guid = Guid.NewGuid();
        string uniqueSubFolderName = guid.ToString();
        string uniquePath = dirPath + uniqueSubFolderName;

    }
    while (Directory.Exists(d.uniquePath));
    Directory.CreateDirectory(d.uniquePath);

    //copy files to new unique directory
    string wisppUnique = Path.Combine(d.uniquePath, "WisppNew.exe");
    string fortranUnique = Path.Combine(d.uniquePath, "libf60rts.dll");
    string wisppGraphUnique = Path.Combine(d.uniquePath, "WISPPGRA");
    string excelUnique = Path.Combine(d.uniquePath, "WISPP_Template.xls");
    string excelOutput = Path.Combine(d.uniquePath, "WISPP_Output.xls");
    File.Copy(wisppExe, wisppUnique, true);
    File.Copy(fortranLib, fortranUnique, true);
    File.Copy(excelTemplate, excelUnique, true);

    //write data into excel        
    FileStream outputFile = new FileStream(excelOutput, FileMode.OpenOrCreate, FileAccess.Write);
    xssfworkbook.Write(outputFile);
    outputFile.Close();

    yourButton2.Visible = true;

    yourButton2.Click += (_sender, _e) =>
    {
        //excelOutput is still in scope
        FileInfo file = new FileInfo(excelOutput);

        if(file.Exists)
        {
            Response.Clear();
            Response.ClearHeaders();
            Response.ClearContent();
            Response.AddHeader("Content-Disposition", "attachment; filename=" + file.Name);
            Response.AddHeader("Content-Length", file.Length.ToString());
            Response.ContentType = "Application/x-msexcel";
            Response.Flush();
            Response.TransmitFile(file.FullName);
            Response.End();
        }
    };
}

Answer 2

谢谢@metal_man会议有所作为。好又简单。

我在定义了我独特的excel路径之后添加了这个。

    Session["excelPath"] = excelOutput;

这是我点击按钮2

    string excelOutput = (string)Session["excelPath"];

关于会话状态的好文章 http://www.codeproject.com/Articles/32545/Exploring-Session-in-ASP-Net

按钮上定义的传递变量点击另一个按钮单击c＃

2 个答案: