重新排序文本文件 - Python

时间:2015-11-17 11:45:33

标签: python file text input output

我必须重新订购输入文件,然后将输出打印到新文件。

这是输入文件:

 The first line never changes.  
 The second line was a bit much longer.  
 The third line was short.  
 The fourth line was nearly the longer line.    
 The fifth was tiny.  
 The sixth line is just one line more.                  
 The seventh line was the last line of the original file. 

这是输出文件的样子:

 The first line never changes.                                            
 The seventh line was the last line of the original file.
 The second line was a bit much longer. 
 The sixth line is just one line more.
 The third line was short. 
 The fifth was tiny. 
 The fourth line was nearly the longer line.

我的代码已经反转输入文件并将其打印到输出文件,如下所示

ifile_name = open(ifile_name, 'r')
lines = ifile_name.readlines()
ofile_name = open(ofile_name, "w")

lines[-1] = lines[-1].rstrip() + '\n'
for line in reversed(lines):
        ofile_name.write(line)
ifile_name.close()
ofile_name.close()

无论如何,我可以在文本文件中获得所需的格式,同时保留我的反向代码吗?

如打印输入文件的第一行,然后反转并打印该行,打印输入文件的第二行,然后反转并打印该行等。

很抱歉,如果这看起来不太清楚我对Python和堆栈溢出很新。

提前致谢。

2 个答案:

答案 0 :(得分:1)

如果您不关心生成的列表,我认为这是一个非常优雅的解决方案。

with open("ifile_name","r") as f:
    init_list=f.read().strip().splitlines()

with open("result.txt","a") as f1:
    while True:
        try:
            f1.write(init_list.pop(0)+"\n")
            f1.write(init_list.pop()+"\n")
        except IndexError:
            break

答案 1 :(得分:0)

ifile_name = "hello/input.txt"
ofile_name = "hello/output.txt"
ifile_name = open(ifile_name, 'r')
lines = ifile_name.readlines()
ofile_name = open(ofile_name, "w")

lines[-1] = lines[-1].rstrip() + '\n'
start = 0
end = len(lines) - 1
while start < end:
    ofile_name.write(lines[start])
    ofile_name.write(lines[end])
    start += 1
    end -= 1
if start == end:
    ofile_name.write(lines[start])
ifile_name.close()
ofile_name.close()

使用两个枢轴startend来指向要写入文件的行。 在start == end后,将中间行写入文件