Question

我想找到过去30天的移动平均线。例如

今天的日期是17/11/15，我的数据只有几天

原始数据

date           qty      
06/11/15        5       
08/11/15        7       
09/11/15        8       
10/11/15        12      
11/11/15        34      
15/11/15        45      
16/11/15        12      
17/11/15        7

查找30天移动平均数据 - 需要获得movingAvg，如下表-movingAvg列

date        qty     movingAvg

17/10/15        0       0   
18/10/15        0       0    
19/10/15        0       0    
20/10/15        0       0    
21/10/15        0       0   
22/10/15        0       0   
23/10/15        0       0   
24/10/15        0       0   
25/10/15        0       0    
26/10/15        0       0    
27/10/15        0       0   
28/10/15        0       0   
29/10/15        0       0   
30/10/15        0       0   
31/10/15        0       0    
01/11/15        0       0    
02/11/15        0       0   
03/11/15        0       0   
04/11/15        0       0    
05/11/15        0       0    
06/11/15        5       0.14    
07/11/15        0       1.4    
08/11/15        7       0.4    
09/11/15        8       0.67    
10/11/15        12      1.06    
11/11/15        34      2.2    
12/11/15        0       2.2    
13/11/15        0       2.2    
14/11/15        0       2.2
15/11/15        45      3.7    
16/11/15        12      4.1   
17/11/15        7       4.33

请帮我解决这个问题，或者是否有替代方案。

Answer 1

使用MySQL str_to_date或INTERVAL

select date,qty,avg(qty) from table    
WHERE str_to_date(date,'%d/%m/%y') >= DATE(NOW()) - INTERVAL 30 DAY 
GROUP BY date

Answer 2

有很多方法可以给这只猫上皮。这是一个使用日历表的所有合理日期（一个令人沮丧的小数据集）...

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Answer 3

生成一系列日期，并将其与原始数据相结合。加入两次，一次获得数天，一次获得过去30天的平均值。

SELECT sub0.aDate, IFNULL(od1.qty, 0), AVG(IFNULL(od2.qty, 0))
FROM
(
    SELECT DATE_SUB( CURRENT_DATE(), INTERVAL (units.a + tens.a * 10) DAY) AS aDate, DATE_SUB( CURRENT_DATE(), INTERVAL ((units.a + tens.a * 10) + 29) DAY) AS prevDate
    FROM
    (SELECT 0 a UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) units
    CROSS JOIN
    (SELECT 0 a UNION SELECT 1 UNION SELECT 2) tens
) sub0
INNER JOIN
(
    SELECT DATE_SUB( CURRENT_DATE(), INTERVAL (units.a + tens.a * 10) DAY) AS aDate
    FROM
    (SELECT 0 a UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) units
    CROSS JOIN
    (SELECT 0 a UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5) tens
) sub1
ON sub1.aDate BETWEEN sub0.prevDate AND sub0.aDate
LEFT OUTER JOIN original_data  od1 ON od1.`date` = sub0.aDate
LEFT OUTER JOIN original_data  od2 ON od2.`date` = sub1.aDate
GROUP BY aDate, od1.qty
ORDER BY aDate

Answer 4

试试这个......

SELECT * FROM  your_table
WHERE date >= DATEADD(day,-30, now()) AND date <= now()

希望这会有所帮助..

如何查找过去30天内所有日期的移动平均线，日期间隔为0

4 个答案: