我正在尝试通过Javscript web api调用的web api将文件从本地计算机上传到sharepoint。试图将文件对象从javascript传递到web api,但我一直在收到类型错误,资源未找到等错误。任何人都可以帮忙。
Javascript代码:
$scope.Upload = function () {
if (!window.FileReader) {
alert("This browser does not support the HTML5 File APIs");
return;
}
var element = document.getElementById("uploadInput");
var file = element.files[0];
//var folderStructure = "/PublishingImages/Lists/Featured%20Stories/";
var parts = element.value.split("\\");
var fileName = parts[parts.length - 1];
filename1 = fileName;
var descriptionName = fileName;
var reader = new FileReader();
var indentifier = '';
//url = encodeURI(url);
reader.onload = function (e) {
UploadDocs(e.target.result, fileName);
}
reader.onerror = function (e) {
alert(e.target.error);
}
reader.readAsArrayBuffer(file);
}
function UploadDocs(str, file) {
var url = webApiUrl + "api/Registration/UploadFileToDocmentLibrary";
$.ajax({
type: "POST",
url: url,
contentType: 'application/json; charset=utf-8',
data: JSON.stringify(str),
dataType: 'json',
async: false,
success: function (response) {
console.log(response.fileData);
console.log('Success');
},
error: function (data) {
console.log('fail');
}
});
}
Web API代码:
[HttpPost] // This is from System.Web.Http, and not from System.Web.Mvc
public void UploadFileToDocmentLibrary(HttpPostedFile uploadFile)
{
//code to upload to sharepoint
}
答案 0 :(得分:2)
您可以使用FormData
JS:
$scope.uploadDocs = function () {
var element = document.getElementById("uploadInput");
var file = element.files[0];
var loFormData = new FormData();
loFormData.append("filename", file.name);
loFormData.append("file", file);
var loAjaxRequest = $.ajax({
cache: false,
type: 'POST',
url: webApiUrl + "api/Registration/UploadFileToDocmentLibrary",
contentType: false,
processData: false,
data: loFormData
});
loAjaxRequest.done(function (xhr, textStatus) {
alert(textStatus);
});
};
网络API:
[HttpPost]
public async Task<HttpResponseMessage> UploadFileToDocmentLibrary()
{
if (!this.Request.Content.IsMimeMultipartContent())
throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
try
{
var loProvider = new MultipartFormDataStreamProvider(Path.GetTempPath());
await Request.Content.ReadAsMultipartAsync(loProvider);
string lsFilename = loProvider.FormData.GetValues("filename").First();
var loFile = loProvider.FileData.First();
string lsFileContent = File.ReadAllText(loFile.LocalFileName);
return new HttpResponseMessage(HttpStatusCode.OK);
}
catch (Exception exp)
{
return this.Request.CreateErrorResponse(HttpStatusCode.InternalServerError, exp);
}
}