我的项目遇到了问题。 我想使用" Google API"登录我的 LoginActivity 。并从另一个Activity(名为 WelcomeActivity )
注销LoginActivity: (代码为here)
public class LoginActivity extends AppCompatActivity implements
GoogleApiClient.OnConnectionFailedListener,
View.OnClickListener {
// Configuration of Google API - Step 1/3
private static final String TAG = "LoginActivity";
private static final int RC_SIGN_IN = 9001;
public static GoogleApiClient mGoogleApiClient;
private ProgressDialog mProgressDialog;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
GoogleAPI();
}
public void GoogleAPI(){
// Button listeners
findViewById(R.id.sign_in_button).setOnClickListener(this);
GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
.requestEmail()
.build();
mGoogleApiClient = new GoogleApiClient.Builder(this)
.enableAutoManage(this /* FragmentActivity */, this /* OnConnectionFailedListener */)
.addApi(Auth.GOOGLE_SIGN_IN_API, gso)
.build();
}
@Override
public void onStart() {
super.onStart();
....
}
// [START onActivityResult]
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
// Result returned from launching the Intent from GoogleSignInApi.getSignInIntent(...);
if (requestCode == RC_SIGN_IN) {
GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);
handleSignInResult(result);
}
}
// [END onActivityResult]
// [START handleSignInResult]
private void handleSignInResult(GoogleSignInResult result) {
if (result.isSuccess()) {
// Signed in successfully, show authenticated UI.
CustomApplication app = (CustomApplication)getApplication();
GoogleSignInAccount acct = result.getSignInAccount();
Intent i = new Intent(LoginActivity.this, WelcomePage.class);
i.putExtra("Username", acct.getDisplayName());
startActivity(i);
}
}
// [END handleSignInResult]
// [START signIn]
private void signIn() {
Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(mGoogleApiClient);
startActivityForResult(signInIntent, RC_SIGN_IN);
}
// [END signIn]
@Override
public void onConnectionFailed(ConnectionResult connectionResult) {
...
}
private void showProgressDialog() {
...
}
private void hideProgressDialog() {
...
}
@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.sign_in_button:
signIn();
break;
….
}
}
}
我想在欢迎活动中使用Sign_out方法,
private void signOut() {
// Auth.GoogleSignInApi.signOut(mGoogleApiClient).setResultCallback(
// new ResultCallback<Status>() {
// @Override
// public void onResult(Status status) {
// // [START_EXCLUDE]
//// updateUI(false);
// // [END_EXCLUDE]
// }
// });
// }
为了解决这个问题,我尝试了两种方法:
将mGoogleApiClient作为全局变量(扩展Application或Singleton),我试试,但失败了,在欢迎页面中,mGoogleApiClient不为空,但错误是: mGoogleApiClient尚未连接
我调用了LoginActivity.getMGoogleApiClient(静态变量),但也失败了,同样的错误: mGoogleApiClient尚未连接。
我已经搜索了这个问题好几天了,但解决它没什么用处,请帮帮我..
答案 0 :(得分:6)
当你启用自动管理时,googleApiClient会在onStart上连接并在onStop上断开连接,并由库自动处理。您可以在其他活动中注销用户,无论您的代码是从后端注销用户,除了不要从谷歌退出。
伪代码:
private void logOut(){
//your logout code in the log out activity
setCurrentUser(null);
}
在使用googleApiClient的活动中,您可以检查用户是否登录了googleApiClient的onConnected回调。如果当前用户未登录,请从Google注销该用户。
@Override
public void onConnected(Bundle connectionHint) {
if (getCurrentUser() == null){
signOut();
}
}
private void signOut() {
Auth.GoogleSignInApi.signOut(mGoogleApiClientPlus).setResultCallback(
new ResultCallback<Status>() {
@Override
public void onResult(Status status) {
//signed out.
}
});
}
如果你没有使用enableAutoManage并且没有断开onStop上的客户端(我不知道它是否推荐),你可以使用你的2种方法,但我赢了&建议对googleApiClient对象使用静态字段。
答案 1 :(得分:1)
一种解决方案是执行正常的注销流程(忽略mGoogleApiClient)。下次用户将您的应用程序打开到登录屏幕并点击谷歌登录时,您先将其注销,然后进行谷歌登录
e.g:
private void googleLogin() {
googleLogout();
Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(mGoogleApiClient);
startActivityForResult(signInIntent, RC_SIGN_IN);
}
private void googleLogout() {
if (mGoogleApiClient.isConnected()) {
Auth.GoogleSignInApi.signOut(mGoogleApiClient);
}
}