Question

我有一堆组件需要在每个匹配的生命周期范围内解析（InstancePerMatchingLifetimeScope）。

然而，我必须逐一为它们中的每一个指定它。

e.g。）

builder.RegisterType<LukeSkywalker>().As<IJedi>().InstancePerMatchingLifetimeScope("starwars");
builder.RegisterType<ObiwanKenobi>().As<IJedi>().InstancePerMatchingLifetimeScope("starwars");
builder.RegisterType<MasterYoda>().As<IJedi>().InstancePerMatchingLifetimeScope("starwars");
...

你得到了照片。有没有办法指定＆＃34;所有这些＆＃34;是InstancePerMatchingLifetimeScope？

像（伪代码）：

[
    builder.RegisterType<LukeSkywalker>().As<IJedi>(),
    builder.RegisterType<ObiwanKenobi>().As<IJedi>(),
    builder.RegisterType<MasterYoda>().As<IJedi>(),
].InstancePerMatchingLifetimeScope("starwars");

Answer 1

builder.RegisterType<LukeSkywalker>().As<IJedi>()返回IRegistrationBuilder<out TLimit, out TActivatorData, out TRegistrationStyle>类型的对象，以便您可以为此类型创建自己的方法。

public static class RegistrationsExtensions
{
    public static IRegistrationBuilder<TLimit, TActivatorData, TStyle> InstancePerStarwars<TLimit, TActivatorData, TStyle>(this IRegistrationBuilder<TLimit, TActivatorData, TStyle> registration)
    {
        return registration.InstancePerMatchingLifetimeScope("starwars");
    }
}

并称之为：

builder.RegisterType<LukeSkywalker>().As<IJedi>().InstancePerStarwars()

您还可以创建另一种扩展ContainerBuilder的方法：

public static void InstancePerStarwars<TLimit, TActivatorData, TStyle>(this ContainerBuilder builder, params IRegistrationBuilder<TLimit, TActivatorData, TStyle>[] registrations)
{
    foreach (IRegistrationBuilder<TLimit, TActivatorData, TStyle> registration in registrations)
    {
        registration.InstancePerStarwars();
    }
}

然后，您将能够这样做：

builder.InstancePerStarwars(
    new IRegistrationBuilder<Object, ReflectionActivatorData, SingleRegistrationStyle>[] {
        builder.RegisterType<LukeSkywalker>().As<IJedi>(),
        builder.RegisterType<ObiwanKenobi>().As<IJedi>(),
        builder.RegisterType<MasterYoda>().As<IJedi>()
    });

在相同的匹配生命周期范围内注册多个组件

1 个答案: