Question

我有一个包含一些用户数据的CSV文件，如下所示：

"10333","","an.10","Kenyata","","Aaron","","","","","","","","","",""
"12222","","an.4","Wendy","","Aaron","","","","","","","","","",""
"14343","","aaron.5","Nanci","","Aaron","","","","","","","","","",""

我还有一个文件，每行都有一个项目，如下所示：

an.10
arron.5

我想要的只是找到列表文件中包含的CSV文件中的行。

所以期望的输出是：

"10333","","an.10","Kenyata","","Aaron","","","","","","","","","",""
"14343","","aaron.5","Nanci","","Aaron","","","","","","","","","",""

（注意这个新列表中不包含an.4。）

我有任何可用的环境，除了手动操作之外我愿意尝试任何事情，因为这个csv包含数百万条记录，并且列表中有大约100k条目。

Answer 1

标识符an.10之类的唯一性如何？

也许一个非常小的* x shell脚本就足够了：

for i in $(uniq list.txt); do grep "\"$i\"" data.csv; done

对于列表中的每个唯一条目，都会返回csv文件中的所有匹配行。但它并不完全匹配第二列。（这可以通过例如awk完成）

Answer 2

如果csv文件是data.csv而列表文件是list.txt，我会这样做：

for i in `cat list.txt`; do grep $i data.csv; done

如何找到csv文件和仅包含此csv的一列的文件之间的区别

2 个答案: