所以我的代码块类似于:
public class Task {
private Long id;
private String description;
private Date dueDate;
// getters and setters here
public List<Task> getAllTasks(){
String sql =
"SELECT id, description, duedate " +
"FROM tasks";
try(Connection con = sql2o.open()) {
return con.createQuery(sql).executeAndFetch(Task.class);
}
}
}
(还有一个getID方法和getDesc方法遗漏了) 我可以运行这样的东西来获取它返回的列表中的对象:
Task myTask1 = Task.getAllTasks().get(0);
如果我试着像这样打印id或desc
System.out.println(myTask1.getID());
System.out.println(myTask1.getDesc());
我总是得0和null,这不是正确的值。我需要做些什么才能让它发挥作用?
答案 0 :(得分:0)
如果您只想打印SQL结果,可以通过调用executeAndFetchTable()
并迭代返回的org.sql2o.data.Table
对象。以下是示例代码:
import org.junit.Test;
import org.sql2o.Connection;
import org.sql2o.Sql2o;
public class Sql2oTest {
@Test
public void testSql2oTable() {
Sql2o sql2o = new Sql2o("jdbc:postgresql://10.9.8.7:5432/testdb", "utest", "password");
try (Connection con = sql2o.open()) {
con.createQuery("SELECT * FROM pg_catalog.pg_tables")
.executeAndFetchTable() // No entity class needed
.rows() // List<org.sql2o.data.Row>
.stream() // Java 8 stream
.forEach(row -> // print what you want
System.out.println(row.getString(1) +
", " + row.getObject(2) +
", " + row.getObject("hasindexes")));
}
}
}