所以我需要创建一个只接受候选人的ArrayList ...
然后将其添加到列表
我认为这是我的代码所做的,但它不打印任何东西。由于它没有出现任何错误,它让我相信它并没有真正地反复出现。或者它遍历第一个(不符合标准)并停止,因此它将无法打印任何内容。我查了一些其他的例子,尝试实现和改变一些东西,但它仍然无法正常工作。对我来说,它看起来应该工作,所以我无法弄清楚要改变什么。
任何建议都会受到重视!
import java.util.ArrayList;
public class Candidate extends AddressBook {
private boolean innovation;
private double grade;
private double regulation;
private String communication;
public Candidate(String fn, String ln, double grade, String comm,
boolean innov, double reg) {
super(fn, ln);
this.grade = grade;
this.communication = comm;
this.innovation = innov;
this.regulation = reg;
}
public boolean isInnovative() {
return innovation;
}
public double getGrade() {
return grade;
}
public double getRegulation() {
return regulation;
}
public String getCommunication() {
return communication;
}
public static ArrayList<Candidate> getEligibleCandidates(Candidate[] cands) {
ArrayList<Candidate> eligibleCandidates = new ArrayList<Candidate>();
Candidate person = cands[0];
for (Candidate i : cands) {
while (i.getGrade() < 85) {
if (i.getRegulation() >= 0.5) {
if (i.getCommunication().equals("average")
|| i.getCommunication().equals("excellent")) {
person = i;
eligibleCandidates.add(i);
}
}
}
}
return eligibleCandidates;
}
public void setCommunication(String comm) {
this.communication = comm;
}
public void setGrade(double grade) {
this.grade = grade;
}
public void setInnovation(boolean innov) {
this.innovation = innov;
}
public void setRegulation(double reg) {
this.regulation = reg;
}
public static void main(String[] args) {
Candidate r1 = new Candidate("Elena", "Brandon", 82.30, "poor", true,
0.5);
Candidate r2 = new Candidate("Thomas", "Molson", 85.10, "poor", false,
1.0);
Candidate r3 = new Candidate("Hamilton", "Winn", 77.77, "average",
false, 0.8);
Candidate r4 = new Candidate("Suzie", "Sarandin", 69.93, "average",
false, 0.0);
Candidate r5 = new Candidate("Philip", "Winne", 93.03, "average", true,
1.0);
Candidate r6 = new Candidate("Alex", "Trebok", 88.61, "poor", true, 0.7);
Candidate r7 = new Candidate("Emma", "Pivoto", 55.99, "excellent",
false, 0.8);
Candidate r8 = new Candidate("John", "Lenthen", 87.49, "excellent",
true, 0.9);
Candidate r9 = new Candidate("James", "Lean", 88.00, "excellent",
false, 0.5);
Candidate r10 = new Candidate("Jane", "Ostin", 91.20, "average", true,
0.6);
Candidate r11 = new Candidate("Emily", "Car", 66.79, "excellent",
false, 0.3);
Candidate r12 = new Candidate("Daniel", "", 76.65, "average", true, 0.2);
Candidate r13 = new Candidate("Neda", "Bazdar", 55.89, "excellent",
true, 0.5);
Candidate r14 = new Candidate("Aaron", "Smith", 90.01, "excellent",
false, 0.3);
Candidate r15 = new Candidate("Kate", "Hen", 87.9, "poor", false, 0.8);
Candidate[] cands = { r1, r2, r3, r4, r5, r6, r7, r8, r9, r10, r11,
r12, r13, r14, r15 };
ArrayList<Candidate> people = Candidate.getEligibleCandidates(cands);
System.out.println(people);
}
}
答案 0 :(得分:1)
因为
而停止for (Candidate i : cands) {
while (i.getGrade() < 85) {
if (i.getRegulation() >= 0.5) {
if (i.getCommunication().equals("average")
|| i.getCommunication().equals("excellent")) {
person = i;
eligibleCandidates.add(i);
}
}
}
}
一旦进入而考虑它(i.getGrade()&lt; 85)它永远不会改变条件的值以摆脱循环。这将是一个无休止的循环。你需要将其改为if语句
for (Candidate i : cands) {
if (i.getGrade() < 85) {
if (i.getRegulation() >= 0.5) {
if (i.getCommunication().equals("average")
|| i.getCommunication().equals("excellent")) {
person = i;
eligibleCandidates.add(i);
}
}
}
}
答案 1 :(得分:0)
一旦您的代码输入while (i.getGrade() < 85)
,它就永远不会退出。那应该是if
检查,而不是循环。你永远不会在loop
内部改变你正在检查的人,所以一旦真实,它将永远是真的。
例如,对于“Elena”,循环将执行并检查is Elena's grade < 85?
。既然如此,就会进入循环。然后,一旦循环完成处理,它将返回到循环的顶部并检查is Elena's grade STILL less than 85?
,这将是真的,因为它在循环中从未改变。
您应该使用if
支票,如下所示。
for (Candidate currentCandidate : cands) {
if(currentCandidate.getGrade()<85 && currentCandidate.getRegulation() >= 0.5 && (currentCandidate.getCommunication().equals("average") || currentCandidate.getCommunication().equals("excellent"))){
eligibleCandidates.add(currentCandidate);
}
}
答案 2 :(得分:0)
应该是:
if ((i.getGrade() < 85) &&
(i.getRegulation() >= 0.5) &&
(i.getCommunication().equals("average") || i.getCommunication().equals("excellent"))) {
person = i;
eligibleCandidates.add(i);
}
}
}
...而不是while ...