Question

我正在使用ruby gem：prawn和扩展名prawn-table来为大虾提供创建表的功能。

当您拥有静态数据时，使用对象displayed here创建表的基础知识是直截了当的：

[["0"; "0"]; ["0"; "1"]; ["1"; "0"]; ["1"; "1"]]

[[0; 0]; [0; 1]; [1; 0]; [1; 1]]

大。那不错。但现在我想迭代一个活动的记录关系对象，但我的尝试只是不起作用：

# This works.  Easy because it is static data
def prepare_for_print
  pdf = Prawn::Document.new
  pdf.font_size 11
  pdf.font "Times-Roman"

  pdf.table([ ["short", "short", "loooooooooooooooooooong "*30],
              ["short", "loooooooooooooooooooong "*15, "short"],
              ["loooooooooooooooooooong "*10, "short", "short"] ])
  return pdf
end

问题在于迭代相关的调用：

def prepare_for_print
  pdf = Prawn::Document.new
  pdf.font_size 11
  pdf.font "Times-Roman"


  calls_by_disability.each do |disability|
    pdf.text "#{disability}", style: :bold, color: "001133"
    pdf.table([ ["Call ID", "Date", "County", "Service Category", "Service", "Notes"],
              disability.calls.each do |call|
                ["hello", "world", "foo", "bar", "bazz", "adsfsa"],
              end
              ])
  end
  return pdf
end

任何提示都表示赞赏。谢谢！

Answer 1

var input = ["that", "thing", "thing", "that", "thing", "that", "thing", "thing", "thing"];
var output = [];
for (var idx = input.indexOf("that", 1); idx !== -1; idx = input.indexOf("that", 1)) {
    output.push(input.splice(0, idx));
}
output.push(input);

Prawn-table：迭代通过Active Record Relation Object填写内容

1 个答案: