我尝试使用其uri将手机图库中的图像添加到gridView中。 不幸的是,它没有做任何事情,我似乎无法找到一种方法让它发挥作用。
我的适配器:
public class ImageGridAdapter extends BaseAdapter {
public Uri imageUri;
private Context mContext;
public ImageGridAdapter(Context c) {
this.mContext = c;
}
@Override
public int getCount() {
return 0;
}
@Override
public Object getItem(int position) {
return null;
}
@Override
public long getItemId(int position) {
return 0;
}
public View getView(int position, View convertView, ViewGroup parent) {
imageUri = PictureGroupActivity.selectedImage;
ImageView imageView;
if (convertView == null) {
imageView = new ImageView(mContext);
imageView.setLayoutParams(new GridView.LayoutParams(85, 85));
imageView.setScaleType(ImageView.ScaleType.CENTER_CROP);
imageView.setPadding(8, 8, 8, 8);
} else {
imageView = (ImageView) convertView;
}
imageView.setImageURI(null);
imageView.setImageURI(imageUri);
return imageView;
}
}
adpater应该从onActivtyResult获取imageUri:
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
gridView = (GridView)findViewById(R.id.picture_group_gridView);
if (requestCode == RESULT_LOAD_IMAGE && resultCode == RESULT_OK && null != data) {
selectedImage = data.getData();
String[] filePathColumn = {MediaStore.Images.Media.DATA};
Toast.makeText(PictureGroupActivity.this, "selectedImage ma hodnotu: " + selectedImage, Toast.LENGTH_SHORT).show();
}
}
我已将myCreate中的gridView设置为我的活动内容:
GridView gridView = (GridView)findViewById(R.id.picture_group_gridView);
gridView.setAdapter(new ImageGridAdapter(this));
gridView.invalidateViews();
gridView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
Toast.makeText(PictureGroupActivity.this, "You clicked " + position, Toast.LENGTH_SHORT).show();
}
});
从图库中选择照片时,gridView仍为空。你如何让它发挥作用?我究竟做错了什么 ?提前谢谢。
答案 0 :(得分:0)
如果您始终从getCount()
返回0,那么您的列表将始终为空。同样,您需要从getItem()
返回一些内容,以便您的View知道哪些数据与哪个列表项相关联。您可能希望使用更具体的Adapter
实现,例如ArrayAdapter
,可以为您处理其中一些。
答案 1 :(得分:0)
dict