Question

我在StackOverflow上发现了一些类似的问题，但我的问题不同了。我会尽力解释清楚。首先是数组结构：$appointment

Array ( 
  [id_users_provider] => 85  
  [start_datetime] => 2015-11-15 17:15:00  
  [end_datetime] => 2015-11-15 17:15:00  
  [notes] =>  
  [is_unavailable] =>  
  [id_users_customer] => 87  
  [id_services] => 15 
)
Array (  
  [id_users_provider] => 85  
  [start_datetime] => 2015-11-15 17:15:00  
  [end_datetime] => 2015-11-15 17:15:00  
  [notes] =>  
  [is_unavailable] =>  
  [id_users_customer] => 87  
  [id_services] => 13  
)

如何看待$appointment变量中包含两个数组。现在我想得到最后一个数组的结尾，在本例中是带有id_services的数组：13。我实际上是通过appointment['id_services']执行迭代。像这样：

foreach($appointment['id_services'] as $services)
{
   print_r(end($appointment));
}

但这回复了我：

15
13个

这是错误的，因为我想在这种情况下只得到13。我怎么能这样做？主要问题是如果实际$services是foreach循环中最后一个数组的最后一个键，则检查foreach循环内部。

Answer 1

伙计，为什么不只是end($appointment)['id_services']？在这种情况下，为什么需要foreach？

$last_appointment = end($appointment);
$id_services = $last_appointment['id_services'];
$id_services === 13; // true

Answer 2

你的foreach循环是错误的....

两种简单的方法......

// using count (not recommended)
echo $appointment[count($appointment)-1]['id_services'];


//using end
echo end($appointment)['id_services'];

根据您的评论，您可能会尝试这样做（我不明白为什么）

$last_appointment = end($appointment);
echo end($last_appointment);

修复代码

//not recommended!!
foreach(end($appointment) as $services)
{
   print_r(end($services));
}

如何在foreach迭代中获取最后一个数组索引？

2 个答案: