我有类型A的节点和类型B的节点 我想匹配B的A和Y节点的X节点,并在所有那些A和所有那些B之间建立关系
到目前为止我是否尝试过(X = 2,Y = 2):
MATCH (a:A) WITH a,rand() AS rand1 ORDER BY rand1 desc LIMIT 2
MATCH (b:B) WITH a,b,rand() AS rand2 ORDER BY rand2 desc LIMIT 2
CREATE (a)-[i:IN]->(b)
RETURN a,i,b
但是,每个选定的A和B只能创建1个连接 例如:
a1-IN->b1
a2-IN->b2
我希望能够创建所有排列:
a1-IN->b1
a1-IN->b2
a2-IN->b1
a2-IN->b2
有什么想法吗?
答案 0 :(得分:2)
这个怎么样?
MATCH (a:A) WITH a, rand() AS rand ORDER BY rand LIMIT 2
WITH collect(a) AS as
MATCH (b:B) WITH b, rand() AS rand ORDER BY rand LIMIT 2
WITH as, collect(b) AS bs
UNWIND as AS a
UNWIND bs AS b
CREATE (a)-[i:IN]->(b)
RETURN a,i,b