对于像这样的简单案例,Springfox无法正确生成swagger文档:
GET /api/departments - Gets all department
GET /api/departments?name=IT - Gets a department with name passed as query parameter
这是Spring Controller:
@ApiOperation(value = "Gets all departments", notes = "", tags = {"departments"})
@RequestMapping(value="/departments", produces=MediaType.APPLICATION_JSON_VALUE, method=RequestMethod.GET)
public List<Department> getAllDepartments(){
...
}
@ApiOperation(value = "Gets a department by name", notes = "", tags = {"departments"})
@RequestMapping(value="/departments", params="name", produces=MediaType.APPLICATION_JSON_VALUE, method=RequestMethod.GET)
public Department getDepartmentByName(@RequestParam String name){
...
}
生成的swagger文件只包含GET / api / departments条目,而不是查询过滤器的跟踪。
任何解决方法?
Swagger配置:
@Bean
public Docket departmentsV1Api() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.any())
.paths(PathSelectors.regex("/.*"))
.build()
.apiInfo(new ApiInfo("Departments Rest API","","v1","","","",""))
.pathMapping("/api")
.securitySchemes(newArrayList(apiKey()))
.securityContexts(newArrayList(securityContext()))
.groupName("departmentsV1");
}
答案 0 :(得分:2)
规范不支持此用例。但是,您可以使用enableUrlTemplating(true)
中的docket
方法启用rfc6570支持。
还有一个实验库(springfox-swagger-ui-rfc6570),可用作标准springfox-swagger-ui
的替代品。
注意: 请记住,这是在孵化中,并且可以在规范中添加支持时更改。
答案 1 :(得分:0)
您需要使用@ApiParam
注释方法参数,例如:
@ApiOperation(value = "Gets a department by name", notes = "", tags = {"departments"})
@RequestMapping(value="/departments", params="name", produces=MediaType.APPLICATION_JSON_VALUE, method=RequestMethod.GET)
public Department getDepartmentByName(@ApiParam(name = "name", value = "name") @RequestParam String name){
...
}